Vector Space Solutions for Systems: Explained Here

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SUMMARY

The discussion clarifies that a solution set for a system of linear equations is not generally a vector space unless it contains only the unique solution, which is the zero vector. Specifically, vector spaces must be closed under scalar multiplication, and if a scalar b (not equal to 1) is applied to a solution X, the result bX does not remain a solution unless Y is the zero vector. Therefore, the solution set of a system of homogeneous equations forms a subspace, particularly when the rank of the system is lower than the number of unknowns.

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  • Understanding of linear equations and their solutions
  • Knowledge of vector spaces and their properties
  • Familiarity with scalar multiplication in vector spaces
  • Concept of subspaces in linear algebra
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  • Learn about homogeneous equations and their solution sets
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Students and professionals in mathematics, particularly those studying linear algebra, as well as educators seeking to clarify concepts related to vector spaces and solution sets.

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Hi everyone,
general question: is a solution set for a particular system a vector space? I know it can be if there is a unique solution, but is it generally true?
Could someone explain, please?

Thanks.
 
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No. Vector spaces are closed under scalar multiplication. If b is a scalar not equal to 1, Y is non-zero, and X is a solution of AX = Y, then:

A(bX) = b(AX) = bY is not equal to Y, so (bX) is not a solution, so the set of solutions is not closed under scalar multiplication, so the set of solutions is not a vector space. Perhaps I've misinterpreted your question. If there is a unique solution, then there would only be that 1 element of the vector space. The only vector space that has only one element is the degenerate vector space {0}.
 
For a particular system? Do you mean a system of linear equations?

The solution set of a system of homogenous equations is a subspace.

If the system consists of n independent equations in n unknowns, then it is just the 0 vector but if the rank is lower than the number of unknowns, then it is a non-trivial subspace of Rn[/sub].
 

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