Calculating Needed Volume of 15 g/L Salt Solution for 12 g/L Solution

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SUMMARY

The discussion centers on calculating the volume of a 15 g/L salt solution required to create 50 mL of a 12 g/L solution. The formula used is C1 * V1 = C2 * V2, where C1 is the concentration of the initial solution, V1 is the volume of the initial solution, C2 is the concentration of the final solution, and V2 is the volume of the final solution. The correct calculation shows that 0.04 L (or 40 mL) of the 15 g/L solution is needed to achieve the desired concentration.

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  • Understanding of concentration calculations in chemistry
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  • Ability to convert between liters and milliliters
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Chemistry students, laboratory technicians, and anyone involved in solution preparation and concentration calculations will benefit from this discussion.

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A salt solution has a concentration of 15 g/L. How much of this solution is needed to make 50 ml of a solution which has a concentration of 12 g/L.

Using [tex]C_1 * V_1= C_2* V_2[/tex](concentration and volume) I got .4 L of this solution must be added.
I didn't really know how to tackle this one so maybe (if I'm wrong, which I probably am) could someone help me out?
 
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NO,the answer should be 0.04L=40mL.Maybe that's what u've gotten and what u've written is just a typo...

Daniel.
 
Ya, it wasn't a typo in my post, it was just a silly mistake on paper, but I found it. Thanks dexter.
 

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