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Circular motion power |
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| Jun27-12, 06:03 AM | #52 |
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Circular motion power[tex]P = F\cdot v[/tex] I don't know how they are assumed to be in the same direction.
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| Jun27-12, 07:59 AM | #53 |
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Perhaps the problem meant to say that the tangential acceleration varies as ....
Then the answer stated in the problem would be correct. |
| Jun27-12, 08:04 AM | #54 |
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| Jun27-12, 08:28 AM | #55 |
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Mentor
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http://www.google.com/search?q=A+par...cceleration%22 Many just keep the question in its original form, a multiple choice question with choices 2πmk2r2t, mk4r2t5/3, mk2r2t, and zero. Some change the choices, others make the question open ended (not multiple choice). A small number of those books provide solutions -- including some erroneous ones (e.g., the book that is the subject of this thread). Apparently it is easy for authors to get their hands on the old test questions, but not on the old test answers. |
| Jun27-12, 09:24 AM | #56 |
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Click Me
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| Jun27-12, 10:51 AM | #57 |
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D H,
It looks like TSny found the real reason why my method did not work. TSny, Thanks for your insight. ehild, Ratch |
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