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Linear motion with variable forces |
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| Jun26-12, 09:27 PM | #1 |
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Linear motion with variable forces
1. The problem statement, all variables and given/known data
A racing car of mass 20000kg accelerates with a driving force of 480(t-10)^2 newtons until it reaches its maximum speed after 10 seconds. Find its maximum speed, and the distance it travels in reaching this speed. 3. The attempt at a solution Again, I can't seem to get the distance travelled after the second integration. m=2000kg F=480(t-10)^2 a=F/m = 6(t-10)^2/25 v=∫a dt =[6(t-10)^3/3]/25 + k Since t=0, v=0 and therefore v=[6(t-10)^3/3]/25 Vmax is found out to be 80m/s But integration of v did not give me the answer stated, which is 600m. I got 200m instead. Please include detailed explanations along with the solution. Thanks! :D |
| Jun26-12, 09:50 PM | #2 |
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| Jun27-12, 01:57 AM | #3 |
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Sorry the mass is 2000kg. :)
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| Jun27-12, 03:21 AM | #4 |
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Linear motion with variable forces
For the velocity you can also use F=dp/dt
[itex]\int_0^t \! f(t) \, \mathrm{d} t. =\int_0^v \! f(mv) \, \mathrm{d} v.[/itex] Just find v from acceleration by integral Then find d from v by integral too. |
| Jun27-12, 04:56 AM | #5 |
Recognitions:
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| calculus, integration, linear motion |
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