Calculate volume in combustion

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    Combustion Volume
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Discussion Overview

The discussion revolves around calculating the volume of oxygen (O2) required for the complete combustion of ethane (C2H6) given specific conditions of mass, temperature, and pressure. The scope includes theoretical calculations and application of gas laws.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant inquires about the volume of O2 needed for the combustion of 152 g of C2H6 at 19.0°C and 100.0 kPa.
  • Another participant calculates the moles of C2H6 as 152 g divided by 30 g/mol but encounters difficulties in the next steps.
  • A suggestion is made to set up the balanced equation for the combustion reaction and use it to determine the moles of O2 required.
  • Participants discuss using the ideal gas law (PV=nRT) to solve for volume, emphasizing the need for the balanced equation and mole ratios.
  • One participant expresses uncertainty about how to set up the calculations and requests assistance.
  • Another participant confirms they balanced the equation and used the mole ratio to find the number of moles, ultimately solving for volume.
  • A later reply offers to double-check calculations if the participant shares their numbers.

Areas of Agreement / Disagreement

Participants generally agree on the steps needed to solve the problem, including balancing the combustion equation and applying the ideal gas law. However, there is no consensus on the specific calculations or final volume, as some participants are still seeking help.

Contextual Notes

Some participants express uncertainty about setting up the calculations and the application of the ideal gas law, indicating potential gaps in understanding or missing assumptions.

Who May Find This Useful

Students or individuals interested in chemistry, particularly in combustion reactions and gas law applications, may find this discussion useful.

parwana
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What volume of O2 (m3) is needed for the complete combustion of 152 g of C2H6 at 19.0oC and 100.0 kPa ?
 
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i found the moles of C2H6 which was 152g/30g/mol

then times that by 292 K and this is where i have trouble
 
First I would set up the balanced equation for the complete combustion reaction. Then, like you did, solve for the number of moles of C2H6, using the balanced equation, determine how many moles of O2 are needed.
then using the eqaution PV=nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin, solve for the volume.
 
i don't know how to set it up though, please help
 
C2H6 reacts with O2, producing CO2 and H2O. Write this down as an equation and balance it.

This is true of any complete combustion...the products are CO2 and H20.
 
i got it, i balanced the equation, and used the mole ratio to find n and finally solved for volume
 
good work...if you'd like someone to double-check your calculations, post your numbers here.
 

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