Formulas for Copper (II) Chlorate

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Homework Help Overview

The discussion revolves around determining the correct chemical formula for copper (II) chlorate, focusing on the oxidation numbers and the composition of the compound.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore different answer choices for the formula, questioning the oxidation states of the elements involved and the nature of the chlorate radical.

Discussion Status

Some participants express confidence in their reasoning while others seek clarification on the oxidation numbers and the logic behind their choices. There is an ongoing exploration of the concepts involved without a clear consensus on the correct answer.

Contextual Notes

Participants discuss the oxidation numbers of copper and the chlorate radical, noting the implications for forming a neutral compound. There are indications of confusion regarding the chemical symbols and terminology used in the question.

seve
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What is the formula for copper (II) chlorate?

a. CuClOsubscript 3
b. Cu(ClOsubscript 3) subscript 2
c. CuCl
d. CuClsubscript 2

Please help if you don't mind.
 
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seve said:
What is the formula for copper (II) chlorate?

a. CuClOsubscript 3
b. Cu(ClOsubscript 3) subscript 2
c. CuCl
d. CuClsubscript 2

Please help if you don't mind.




I don't mind.What's your idea??

Daniel.
 
I believe it is A. I am pretty sure that B and C are wrong because of the oxidation numbers not equaling zero.

Am I correct in my thinking?
 
NO.
What is the ON for each element...??What about the radical "chlorate"...??

Daniel.
 
What is C?
 
What "C" are you talking about...??There's a [itex]Cl[/itex] which is the chemical symbol for Chlore...

Answer the question regarding the ON-s...

Daniel.
 
Sorry, answer choice B.
 
Don't HIT AND RUN...How did u figure it out...??What was your logics??

Daniel.
 
By the process of elimination...

Seriously, though, I don't understand this concept. Can you just explain it to me?

Anyways, thank you for your time and effort if you are too busy.
 
  • #10
The chlorate radical [itex]ClO_{3}[/itex] has ON [itex]-1[/itex] ,simply because the oxygen has ON [itex]-2[/itex] (as in most of its compounds) and the chlore has ON [itex]+5[/itex] (and you should figure out from the suffix "ate" and the lack of any prefix).
On the other side,the copper atom has ON [itex]+2[/itex] (because the problem says so,it may have ON [itex]+1[/itex] as well).
So to form a NEUTRAL MOLECULE,you need two radicals and one copper atom...

Daniel.
 
  • #11
Thanks! I got it.
 

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