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Cylinder oscillating in water. |
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| Jul14-12, 01:12 PM | #1 |
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Cylinder oscillating in water.
ω1. The problem statement, all variables and given/known data
A cylinder of diameter d floats with l of its length submerged. The total height is L. Assume no damping. At time t = 0 the cylinder is pushed down a distance B and released. What is the frequency of oscillation? 2. Relevant equations [itex] f = ω/2\pi [/itex] [itex] Ma = F_{(bouyancy)} [/itex] Writing this in our differential form, making proper substitutions, and noting that bouyancy is affected by the distance that our cylinder is submerged we come to. [itex] dx^2 (M_{(cylinder)}) + x (\rho_{(water)} g Area_{(cylinder face)})= 0 [/itex] we know that [itex]M_{(cylinder)} = V_{(cylinder)}\rho_{(cylinder)} [/itex] hence we should have [itex] ω^2 = (\rho_{(water)} g Area_{(cylinder face)}) / V_{cylinder}\rho_{(cylinder)} = g\rho_{(water)} / l \rho_{(cylinder)}[/itex] however the solution in my problem set has ω^2 = g/l. Can anyone shed some light on why the densities may cancel?? |
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| Jul14-12, 01:30 PM | #2 |
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hi ozone!
![]() i haven't followed what you've done, but i'd guess you've used the wrong expression for the mass of the cylinder ![]() just use a (vertical) force equation for the cylinder (at depth l + x)
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| Jul15-12, 10:42 PM | #3 |
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the mass of the cylinder is the density of the cylinder times the area.. but the force from the water depends only on the density of water.. that is why i don't understand how the densities are cancelled out.
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| Jul15-12, 11:00 PM | #4 |
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Cylinder oscillating in water.
In the denominator of your final expression for ω2, is that a small l or a capital L?
You can find an expression for the ratio of the two densities in terms of the ratio of l and L by considering the condition for equilibrium when length l of the cylinder is submerged. |
| Jul16-12, 09:07 AM | #5 |
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that would be the lower case l in the solution set answer. You can view it for yourself at this link on page 4.
http://ocw.mit.edu/courses/physics/8...ents/sol1b.pdf |
| Jul16-12, 09:41 AM | #6 |
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But in the expression that you derived: ω2 = gρw/lρc, you should have a capital L rather than a lower case l in the denominator. Then you should be able to show that this expression reduces to the correct answer.
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| Jul18-12, 07:28 AM | #7 |
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We never learned about fluid dynamics in my mechanics class, but I am guessing that the water displaced in equilibrium is equal to the mass of the cylinder?
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| Jul18-12, 08:12 AM | #8 |
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In equilibrium, Buoyant force equals the weight of the floating object. |
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