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Can a magnetic fields/forces do work on a current carrying wire?! |
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| Jul23-12, 01:13 PM | #69 |
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Can a magnetic fields/forces do work on a current carrying wire?!
+ Magnets are permanent dipole's
Current carrying loop is considered a temporary dipole?(No electricity not magnetic field) |
| Jul23-12, 01:32 PM | #70 |
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Mentor
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Yes.
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| Jul23-12, 03:22 PM | #71 |
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Thanks DaleSpam,
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| Jul23-12, 03:32 PM | #72 |
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Claude |
| Jul23-12, 05:19 PM | #73 |
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| Jul24-12, 01:41 AM | #74 |
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Recognitions:
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It is very clear that the power of any electromagnetic field on charges is given, according to Poynting's theorem by
[tex]P(t)=\int_{\mathbb{R}^3} \mathrm{d}^3 \vec{x} \; \vec{E}(t,\vec{x}) \cdot \vec{j}(t,\vec{x}).[/tex] Of course a motor does work, but it's the electric field according to the above equation. |
| Jul24-12, 03:15 AM | #75 |
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I believe that my earlier post (13) shows in some detail how this work done by the electric field (post 75) appears as work done on the wire as the wire moves. This electric field is set up by the battery connected across the wire. Throughout this thread I don't think there's been nearly enough emphasis on the battery as the source of the work that's done when the wire moves in the magnetic field.
[Incidentally, for a wire of cross-sectional area A, lying in the ±x direction and carrying current I, vanhees's formula yields Work done per unit time in length [itex]\Delta x[/itex] of wire = [itex](A\Delta x) E_x (\frac{I}{A}) = I E_x \Delta x = -I \Delta V[/itex], which is rather familiar!] |
| Jul24-12, 03:16 AM | #76 |
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Another, related possible point of confusion that I think has been mentioned earlier is that work is typically done through several intermediates, for example you can pull on something heavy with a rope, supporting the force with your feet on the street. Does one then say that the rope does work, or that the street does work? I think that that isn't a common way of formulating things; the permanent magnet acts like the street. |
| Jul24-12, 05:27 AM | #77 |
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If you'd disagree please use equation's to back you're opinion. Because its a known fact the magnets can do work on a dipole(Repel/attract). Now in the case of a motor its stator that is winded up with coil wires generates a magnetic field and acts as a magnet(dipole) thus is attracted/repeled by the magnetic field of the magnets. F = IL x B If you break any system that is doing work, its just applying forces. In some complicated physical systems they apply MULTIPLE FORCES just like a motor. DaleSpam gave out a good point, so as Claude, and Darwin123. If you're still not convinced I'd recommend studying this matter more. Miyz, |
| Jul24-12, 05:31 AM | #78 |
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Ow yea and don't Skimm since you might have skipped a lot of good info.
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| Jul24-12, 06:05 AM | #79 |
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Recognitions:
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Sigh! The equation, I've given is exact (within classical Maxwell theory). A nice paper about this question is the following one. The classical part of it precisely answers the question discussed here on hand of a simple example:
http://link.aps.org/doi/10.1103/PhysRevE.77.036609 |
| Jul24-12, 06:11 AM | #80 |
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| Jul24-12, 06:20 AM | #81 |
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Compare: http://www.lightandmatter.com/html_b...ml#Section13.1 The tractor does work, but the rope does not. |
| Jul24-12, 06:30 AM | #82 |
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Mentor
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On the contrary, the magnetic field does store energy. That energy can be used to do work, every bit as much as the energy stored in a battery or a capacitor can.
http://en.wikipedia.org/wiki/Magneti...agnetic_fields |
| Jul24-12, 06:35 AM | #84 |
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| Jul24-12, 06:38 AM | #85 |
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That WHOLE idea is irrelevant to this topic. |
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