How do i move get rid of a fraction like this?

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Discussion Overview

The discussion revolves around methods for simplifying expressions involving fractions, specifically focusing on the expression (e^x + 1)/e^x. Participants explore different approaches to eliminate the fraction and clarify the simplification process.

Discussion Character

  • Technical explanation, Conceptual clarification, Homework-related

Main Points Raised

  • One participant notes that they can simplify 1/(e^x) to e^-x and seeks clarification on simplifying (e^x + 1)/e^x.
  • Another participant explains that the expression can be broken down using the property of fractions: (a + b)/c = a/c + b/c.
  • A later reply provides a step-by-step breakdown of the simplification, showing that (e^x + 1)/e^x equals 1 + 1/e^x, which can be expressed as e^-1 + 1.
  • One participant corrects another's earlier claim about the simplification process, emphasizing the importance of allowing the original poster to work through the exercise themselves.
  • Another participant suggests a direct answer to the original question, indicating that (e^x + 1) can be multiplied by e^-x to achieve the desired simplification.

Areas of Agreement / Disagreement

Participants present multiple approaches to the simplification, and while there is some agreement on the methods, no consensus is reached on the best approach or the final expression.

Contextual Notes

Some participants express uncertainty about the simplification steps and the importance of understanding the underlying principles rather than just obtaining the answer.

Who May Find This Useful

Students or individuals seeking clarification on simplifying fractional expressions in algebra, particularly those involving exponential functions.

dbzsongoku
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Hi,
Usually for question like 1/(e^x) I can get rid of the fraction by writing it as e^-x. FOr a question like (e^x+1)/e^x how do I do this? It simplifies down to e^-x+1 but I don't get how to do it.
thanks
 
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Because

[tex]\frac{a+b}{c} = \frac{a}{c} + \frac{b}{c}[/tex]
 
edit: dextercioboy: ooh true. sorry! :redface: o:)
 
Last edited:
gazzo said:
[tex] \frac{e^x+1}{e^x} = \frac{e^x}{e^x} + \frac{1}{e^x} = 1 + \frac{1}{e^x} = e^{-1} + 1[/tex]

edit: gah, quasar you're too fast :-p :smile:

You have a typo...And besides,the idea was to make him solve the exercise,not doing it for him...


Daniel.
 
dbzsongoku said:
Hi,
Usually for question like 1/(e^x) I can get rid of the fraction by writing it as e^-x. FOr a question like (e^x+1)/e^x how do I do this? It simplifies down to e^-x+1 but I don't get how to do it.
thanks
A direct answer to your exact question is (e^x + 1)*e^-x, just like your 1/e^x example. :smile: Don't forget the distributive property of multiplication over addition.
 

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