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Calculating the charge distribution on the surface of an assymetric conductor |
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| Jul25-12, 11:49 PM | #1 |
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Calculating the charge distribution on the surface of an assymetric conductor
How do I calculate the charge distribution on the surface of any asymmetric closed conducting surface? Is it possible for me to calculate the surface charge density 'σ' as a function of '[itex]\bar{r}[/itex]' the position vector in a spherical co-ordinate system in space, provided I know that the conductor has been qiven a net charge 'Q' and the equation of the conductor in space is ((x/a)^2)+((y/b)^2)+((z/c)^2)=1...
1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution |
| Jul26-12, 02:16 AM | #2 |
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For any conducting surface you will have to resort to an approximation.
In brief: use a numerical method to establish the Electric field for the system. Use that E field result to establish surface charge distribution. |
| Jul26-12, 01:41 PM | #3 |
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But how do I calculate [itex]\bar{E}[/itex] if I don't know my σ? It's like the chicken egg problem except that it's not what comes first that matters, but I need one to know the other. All I know unfortunately is the shape of the conductor and the total charge Q which according to the uniqueness theorum has a unique way of settling on the surface in the abscence of any external electric field...
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| Jul26-12, 02:21 PM | #4 |
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Calculating the charge distribution on the surface of an assymetric conductor
you don't need to know anything about the charge. Field lines are normal to a conducting surface and themselves normal to equipotentials. This means that you can set up a grid with random starting values for potential and by recalculating each value in turn end up closer to the correct solution.
a quick google gave this http://www.physics.hku.hk/~phys3231/...%20in%202D.pdf The 3d process is very similar. Also http://www.ece.msstate.edu/~donohoe/...techniques.pdf you need the last few pages. The procedure looks hard but really isn't: Though it is a long time since I last did one! |
| Jul26-12, 04:29 PM | #5 |
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Just solve Laplace's equation for the potential. You know that the potential on the surface is a constant (which you may as well set to zero) and that the potential at large distances should look like that of a point charge, so you have your 2 boundary conditions. From the potential, you can determine the charge density.
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