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What is his and how do I solve it?

 
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Jul29-12, 11:23 PM   #18
 
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What is his and how do I solve it?


Quote by Ashir View Post
I realize I can cancel out the -2's but let's say x=3. The expression would be equivalent to:

1+6 (7)
__________ = -7.
-2+1 (-1)
Why are you adding the two terms together in both your numerator and denominator? When you have one bracketed expression directly next to another, you multiply them together, you don't add them:

[tex]\frac{(3-2)(3+3)}{(3-5)(3-2)} =\frac{(1)(6)}{(-2)(1)}=\frac{6}{-2} = -3[/tex]
Jul30-12, 05:03 AM   #19
 
Oh just realized the mistake, thanks.
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