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Use Green's Reciprocation Theorem to show the G.S to the Electrostatic Potential |
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| Aug8-12, 08:04 AM | #1 |
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Use Green's Reciprocation Theorem to show the G.S to the Electrostatic Potential
1. The problem statement, all variables and given/known data
Use Green's Reciprocation Theorem to show the G.S to the Electrostatic Potential 2. Relevant equations Green's Reciprocation Theorem [itex]\int_{v} \rho^{'} \Phi d^{3}x + \int_{s} \sigma^{'} \Phi da = \int_{v} \rho \Phi^{'} d^{3}x + \int_{s} \sigma \Phi^{'} da [/itex] The General Solution to the Electrostatic Potential [itex] \Phi (x,y,z) = \frac{1}{4 ∏ \epsilon_{0}} \int^{+∞}_{-∞} d x^{'} \int^{+∞}_{-∞} d y^{'} \int^{+∞}_{-∞} [ \frac{\rho (x',y',z')}{\sqrt{(x-x')^{2} + (y-y')^{2} + (z-z')^{2}}} - \frac{\rho (x',y',z')}{\sqrt{(x-x')^{2} + (y-y')^{2} + (z+z')^{2}}}]d z^{'} + \frac{1}{4 ∏} \int^{+∞}_{-∞} d x^{'} \int^{+∞}_{-∞} d y^{'} [ \frac{2 z' V (x',y')}{[{(x-x')^{2} + (y-y')^{2} + z'^{2}]^{3/2}}}]d z^{'}[/itex] 3. The attempt at a solution So, I should be able to derive the General Solution to the Electrostatic Potential from the Green's Reciprocation Theorem I have the following to substitute. [itex] \rho ^{'} (\vec{x'}) = 4 ∏ \delta (\vec{x} - \vec{x'}) [/itex] [itex] \Phi ^{'} (x) = G_(D) (\vec{x} ; \vec{x'}) [/itex] [itex] \sigma ^{'} (\vec{x'}) = \epsilon_{0} \frac{∂ G_{D}}{∂{n'}} [/itex] but i don't know how to continue. All of these are just the ones with ' . What would I substitute to those without ' . What should I do? Please help. |
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