Calculate Mass of Sand Grains for Equivalent Cube Surface Area - Physics Problem

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SUMMARY

The discussion focuses on calculating the mass of fine sand grains needed to match the surface area of a cube measuring 1.1 meters on each edge. The surface area of the cube is correctly determined to be 7.986 square meters, while the surface area of a single sand grain, modeled as a sphere with a radius of 50 micrometers, is calculated as 3.14E-8 square meters. The relationship between the surface areas of the cube and the sand grains is established, emphasizing the need to determine the number of grains required to equal the cube's surface area and subsequently calculate the total mass based on the density of silicon dioxide.

PREREQUISITES
  • Understanding of surface area calculations for cubes and spheres
  • Knowledge of density and mass calculations
  • Familiarity with unit conversions, particularly micrometers to meters
  • Basic principles of geometry and physics
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  • Calculate the correct surface area of a cube using the formula for the area of a square
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  • Explore density calculations for various materials, specifically silicon dioxide
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Students studying physics, particularly those focusing on geometry and material properties, as well as educators seeking to clarify concepts related to surface area and mass calculations.

rdn98
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Ok, this is the problem.

Grains of fine sand are approximately sphere of an average radius of of 50 ìm are made of silicon dioxide. A solid cube of this material with a volume of 1m3 has a mass of 2600kg.

Question:
What mass of sand grains would have a total surface area (the total area of all the individual grains) equal to the surface area of a cube 1.1 meters on an edge?

Ok. I figured out the surface area of the cube by taking 1.1m*1.1m*1.1m*6= 7.986m^3

I figured out the surface area of a grain of sand by first converting micrometers into meters, and then plugging that number into the surface area forumula for a sphere.
SA of sphere= 4*pi*(50*10^-6m)^2= 3.14E-8.

Now, somehow the SA of a cube and SA of the grain are related, but I can't get the answer to be accepted by the online homework system. Any ideas?
 
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You probably can't get the answer accepted by the online computer system because it isn't correct!

First of all, surface AREA is not measured in CUBIC meters- it is measured in square meters. You calculated the volume of the cube and then multiplied by 6 to get area? There are, indeed, 6 faces on a cube: each one is a square with edge length 1.1 m: the Area of such a square is ? That's what you want to multiply by 6.

The surface area of the cube and the surface are of the spheres (not just one) are related because the problem tells you they are to be the same! The problem asks for the mass the number of spheres whose surface area is the same as the surface area of the cube.

Once you have found the surface area of the cube (correctly) and the surface area of an individual sphere, determine HOW MANY spheres it would take to have the same surface area as the cube. You can also calculate the volume of each sphere and you are told the density (indirectly) so you can calculate the mass of each sphere. Finally, multiply the mass of each sphere by the number of spheres required.
 
thanks!

Thank you so much. Thank God I found this forum today! :)
 

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