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Oblate spheroid equations

 
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Aug18-12, 10:41 PM   #1
 

Oblate spheroid equations


I'm a little confused by what appears to me to be a paradox. I understand that the equation for an oblate spheroid is given by
\begin{equation}
\frac{x ^ 2+y^2}{a^2} + \frac{z ^ 2}{c^2}= 1, c < a
\end{equation}
where a and c are the semi-major and semi-minor axes respectively.
However, the definitions for the WGS 84 oblate spheroid model of the Earth using the ECEF <--> geodetic latitude/longitude/height are (Wiki Link) the following equations
\begin{equation}
x = N(\phi) cos\phi cos\lambda \\
y = N(\phi) cos\phi sin\lambda \\
z = N(\phi)(1-e^2) sin \phi \\
N(\phi) = \frac{a}{\sqrt{1-e^2 sin^2\phi}}
\end{equation}
where [itex]\phi[/itex] is the geodetic latitude, [itex]\lambda[/itex] is the longitude, e is the eccentricity and a is the semi-major axis. I removed the height parameter as I am only concerned with the spheroid surface.

I have also read a paper which states the equation relating the ECEF X,Y,Z is
\begin{equation}
\frac{x ^ 2+y^2}{N(\phi)^2} + \frac{z ^ 2}{[N(\phi)(1-e^2)]^2}= 1
\end{equation}

The last equation has denominators that depends on the geodetic latitude while the first equation for the oblate spheroid has denominators which are constant. Is there something wrong?
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Aug19-12, 04:26 AM   #2
 
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The equation you quote for an oblate spheroid uses geocentric latitude. I believe the equations on the Wiki page use geodetic latitude. There is a comment about that on the page you linked.
Aug19-12, 04:38 AM   #3
 
Well yes, but isn't ECEF independent of geodetic/geocentric coordinates? Then in the last equation, this seems to suggest that x,y,z must fit a different equation for different geodetic latitudes.
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