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Oblate spheroid equations |
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| Aug18-12, 10:41 PM | #1 |
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Oblate spheroid equations
I'm a little confused by what appears to me to be a paradox. I understand that the equation for an oblate spheroid is given by
\begin{equation} \frac{x ^ 2+y^2}{a^2} + \frac{z ^ 2}{c^2}= 1, c < a \end{equation} where a and c are the semi-major and semi-minor axes respectively. However, the definitions for the WGS 84 oblate spheroid model of the Earth using the ECEF <--> geodetic latitude/longitude/height are (Wiki Link) the following equations \begin{equation} x = N(\phi) cos\phi cos\lambda \\ y = N(\phi) cos\phi sin\lambda \\ z = N(\phi)(1-e^2) sin \phi \\ N(\phi) = \frac{a}{\sqrt{1-e^2 sin^2\phi}} \end{equation} where [itex]\phi[/itex] is the geodetic latitude, [itex]\lambda[/itex] is the longitude, e is the eccentricity and a is the semi-major axis. I removed the height parameter as I am only concerned with the spheroid surface. I have also read a paper which states the equation relating the ECEF X,Y,Z is \begin{equation} \frac{x ^ 2+y^2}{N(\phi)^2} + \frac{z ^ 2}{[N(\phi)(1-e^2)]^2}= 1 \end{equation} The last equation has denominators that depends on the geodetic latitude while the first equation for the oblate spheroid has denominators which are constant. Is there something wrong? |
| Aug19-12, 04:26 AM | #2 |
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Recognitions:
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The equation you quote for an oblate spheroid uses geocentric latitude. I believe the equations on the Wiki page use geodetic latitude. There is a comment about that on the page you linked.
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| Aug19-12, 04:38 AM | #3 |
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Well yes, but isn't ECEF independent of geodetic/geocentric coordinates? Then in the last equation, this seems to suggest that x,y,z must fit a different equation for different geodetic latitudes.
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