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Trig substitutions |
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| Feb8-05, 06:27 PM | #1 |
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Trig substitutions
Our professor today was showing us how to find integrals using trig subsitions.
I was wonder, in a substituation, say, like, x = sin u, how are we entitled to make such a substitution without restricting the values of x, when the sin function's values are between -1 and 1. |
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| Feb8-05, 08:24 PM | #2 |
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Recognitions:
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You will know that the substitution is invalid when you try to determine the new limits of integration. If you have an integral that goes from x=3 to x=5, and you substituted x=sin u, you'll know that you've made a mistake since 3=sinu and 5=sinu have no solutions. |
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