|Feb8-05, 06:27 PM||#1|
Our professor today was showing us how to find integrals using trig subsitions.
I was wonder, in a substituation, say, like, x = sin u, how are we entitled to make such a substitution without restricting the values of x, when the sin function's values are between -1 and 1.
|Feb8-05, 08:24 PM||#2|
You will know that the substitution is invalid when you try to determine the new limits of integration. If you have an integral that goes from x=3 to x=5,
and you substituted x=sin u, you'll know that you've made a mistake since 3=sinu and 5=sinu have no solutions.
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