
#1
Feb1105, 07:10 PM

P: 483

A very long straight wire has charge per unit length 1.49×1010 C/m.
At what distance from the wire is the magnitude of the electric field equal to 2.49 N/C? Use 8.85×1012 C^2/(N*m^2) for the permittivity of free space and use pi = 3.1416 for E = (lambda)/(2*pi*permittivity of free space*r). Given: E = 2.49 N/C I have no idea what to do with this formula. Why is wavelength needed and what is the variable we are trying to find? I am lost. Thanks. 



#2
Feb1105, 07:16 PM

Mentor
P: 40,886





#3
Feb1105, 07:22 PM

Sci Advisor
HW Helper
P: 11,863

[itex] \lambda [/itex] is not a wavelength,it's the linear charge density and it's measured in C/m.
Plug in all the numbers in the formula & see what happens... Daniel. 


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