Why {x^n} /\sum_{0}^{x}x^{n-1}={x-1}/x: Explained

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Homework Help Overview

The discussion revolves around the equation {x^n} /\sum_{0}^{x}x^{n-1}={x-1}/x, exploring its validity and implications within the context of algebraic manipulation and summation.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the structure of the equation, particularly why the variable "n" does not appear in the summation. There is also concern regarding the behavior of both sides of the equation at specific values of "x".

Discussion Status

The discussion is ongoing, with participants expressing skepticism about the equation's soundness and raising questions about its formulation. Some participants suggest that further clarification or explanation may be necessary.

Contextual Notes

There appears to be confusion regarding the summation limits and the role of the variable "n", as well as the behavior of the equation at certain points, such as x=1.

sebasalekhine7
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Can anyone proove why [tex]{x^n} /\sum_{0}^{x}x^{n-1}={x-1}/x[/tex]
 
Last edited:
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Rewrite done.
 
It doesn't look sound to me.If you sum over "x",why doesn't "n" appear in the equation...?

Daniel.
 
Also, in its current form, the Right Side is 0 at x=(1), whereas the Left Side is non-zero at x=(1).
 
There's definitely something weird with this exercise.Maybe he'll explain it,or or just drop it...

Daniel.
 

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