
#1
Sep1412, 03:39 PM

P: 1

1. The problem statement, all variables and given/known data
A kayaker needs to paddle north across a 105 m wide harbor. The tide is going out, creating a tidal current that flows to the east at 1.5 m/s. The kayaker can paddle with a speed of 3.4 m/s. (a) In which direction should he paddle in order to travel straight across the harbor? (degrees west of north) (b) How long will it take him to cross? (seconds) 2. Relevant equations c^2= a^2 + b^2 3. The attempt at a solution I divided 105m by 3.4 m/s to determine how long it would take to go straight across the harbor. Then I multiplied that number (30.88) by 1.5 m/s to get the distance he would have ended up downstream. 46.32m. Then, I attempted to set up a right triangle and solve for the angle but that's where I got confused. 



#2
Sep1412, 07:29 PM

HW Helper
P: 2,316





#3
Sep1412, 07:55 PM

P: 961

1. The problem statement, all variables and given/known data
A kayaker needs to paddle north across a 105 m wide harbor. The tide is going out, creating a tidal current that flows to the east at 1.5 m/s. The kayaker can paddle with a speed of 3.4 m/s. (a) In which direction should he paddle in order to travel straight across the harbor? (degrees west of north) (b) How long will it take him to cross? (seconds) Then, I attempted to set up a right triangle and solve for the angle but that's where I got confused.  Yes you can use a right triangle to solve the problem. This is a vector problem and using a right triangle geometry is one of the methods. Kayaker speed with direction is one vector. The tide speed and direction is another vector. You can do operations on this 2 vectors and in this example adding the two vectors. The sum of the two vectors will result in the kayaker paddling straight across the habour. 



#4
Sep1512, 04:20 AM

P: 2,861

Kayaker paddling across a harbor
What azizlwl said.
If still stuck post your attempt at the vector diagram. 


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