Why Is My Calculation of Current in a 33 Ohm Resistor Incorrect?

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Homework Help Overview

The discussion revolves around a circuit analysis problem involving a 33 ohm resistor. The original poster attempts to calculate the current flowing through this resistor and the potential difference between two points in the circuit, but reports an incorrect result.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the method of calculating equivalent resistance and applying current division. Questions arise regarding the accuracy of the original poster's calculations and the interpretation of the circuit configuration.

Discussion Status

Some participants confirm parts of the original poster's calculations while questioning the method used to find the current through the 33 ohm resistor. There is an ongoing exploration of potential errors, including the possibility of misreading resistor values.

Contextual Notes

The original poster mentions that this is for an online assignment with no provided answers, which may add pressure to resolve the issue correctly. There is also a concern about having only one last attempt to submit the answer.

CartoonKid
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p28-09alt.gif


Consider the circuit shown in Figure P28.9. (R = 33.0 .)

The question ask me to find the current flowing through the 33 ohm resistance and also the potential difference between point a and b.

I consider the 10, 5 and (33+5) to be parallel; 33 is in series with 5.

So the equivalent resistance found by me is 13.06 ohm, thus the total current is 1.91A. Then I apply the current division method and found that the current flowing through the 33 ohm was 0.154A. This answer was wrong!

Somebody please help me. I am quite depressing now. What's wrong with my answer?
 
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13.06 is right as is the 1.91A

Your current through the R leg is wrong though. How exactly did you find that value?
 
First I sum up the 10 and 5 resistance which are parallel. Then i can treat the circuit as if I have 2 resistances in parallel which are 10||5 = 3.33 ohm and (33+5) = 38 ohm. Then, I apply the current division law to find the current flowing through into the 38 ohm.
 
Here's another approach(KVL which I'd use this for simple circuits):

You have 1.91A going through the series 10 ohm resistor thus that resistor is dropping 19.1V.

The parallel legs of the circuit will all have the same voltage drop(by KVL) which will be 25-19.1=5.9V

so, [tex]V_R=5.9V/38=0.154A[/tex]

I'm sorry, I used a total resistance of 52 through the parallel elements(adding in ones head can lead to wrong answers).

Your answer appears to be right.
 
Any chance you miscopied the value R=(33 ohms)? Could it be R=(3.3 ohms)?
Also, what was the answer provided? It may give a clue to the problem here.
 
I have again submitted the answer. The potential difference appears appear to be correct. But the current is still wrong. What's wrong again? I only have one last attempt only. Please help.
 
xanthym said:
Any chance you miscopied the value R=(33 ohms)? Could it be R=(3.3 ohms)?
Also, what was the answer provided? It may give a clue to the problem here.

I have double checked the value, it's really 33.0 ohms. It's an online assignment of mine, so there is no answer provided.
 
Well, 3 people here have all calculated exactly the same results!
 

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