I want to find the expectation value [tex]\langle x^2 \rangle[/tex] in

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Discussion Overview

The discussion revolves around finding the expectation value \(\langle x^2 \rangle\) using a change of variable in a quantum mechanics context. Participants explore the mathematical steps involved in the calculation and the normalization of the wave function.

Discussion Character

  • Mathematical reasoning
  • Conceptual clarification

Main Points Raised

  • One participant describes their approach to calculating \(\langle x^2 \rangle\) by introducing a new variable \(\xi\) and expresses confusion over obtaining incorrect results.
  • Another participant advises ensuring that the wave function \(\psi\) remains correctly normalized when expressed in terms of \(\xi\).
  • A later reply expresses gratitude for the clarification, indicating that the advice was helpful.
  • Humor is introduced in the discussion about expertise and common errors in the field.

Areas of Agreement / Disagreement

Participants appear to agree on the importance of normalization in the calculation, but the initial confusion regarding the expectation value calculation remains unresolved.

Contextual Notes

There is an implicit assumption about the normalization of the wave function that may affect the results, but this is not fully explored in the discussion.

broegger
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I want to find the expectation value [tex]\langle x^2 \rangle[/tex] in some problem. To do this I make a change-of-variable,

[tex]\xi = \sqrt{\frac{m\omega}{\hslash}}x,[/tex]​

and compute the expectation value [tex]\langle \xi^2 \rangle[/tex] like this:

[tex]\langle \xi^2 \rangle = \int\xi^2\vert\psi(\xi)\vert^2d\xi.[/tex]​

Finally I change back to x:

[tex]\langle \xi^2 \rangle = \langle \frac{m\omega}{\hslash}x^2 \rangle = \frac{m\omega}{\hslash}\langle x^2 \rangle \Rightarrow \langle x^2 \rangle = \frac{\hslash}{m\omega}\langle \xi^2 \rangle.[/tex]​

I really can't see what is wrong here, but something is! I've tried it 10 times and I keep getting the wrong result.
 
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broegger said:
[tex]\langle \xi^2 \rangle = \int\xi^2\vert\psi(\xi)\vert^2d\xi.[/tex]​

Be carefull that your psi is still correctly normalized when expressed in xi !

cheers,
Patrick.
 
Yep, that's it :D

Thank you very much! How do you spot these things right away?
 
broegger said:
Yep, that's it :D

Thank you very much! How do you spot these things right away?

Because I'm an expert :blushing:

An expert is someone who has made all possible and imaginable errors in a very small domain :smile:

cheers,
Patrick.
 
I see I'm on the right track, then... :smile:
 

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