Calculating Force for a Space Shuttle with Earth's Gravitational Acceleration

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  • Thread starter Thread starter gnickg
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Discussion Overview

The discussion revolves around calculating the force required to accelerate a 10,000-kg space shuttle to counteract Earth's gravitational acceleration of 9.8 m/s². It includes conceptual clarifications and considerations of gravitational force and acceleration in the context of physics problems.

Discussion Character

  • Conceptual clarification
  • Mathematical reasoning

Main Points Raised

  • One participant calculates the force as 98,000 Newtons by multiplying the gravitational acceleration (9.8 m/s²) by the mass (10,000 kg) and seeks confirmation of this calculation.
  • Another participant confirms the calculation and introduces a follow-up question about the force required for liftoff, hinting at a trick aspect of the problem.
  • A different participant provides a conceptual clarification regarding the term "g," suggesting it is a misnomer and emphasizing that gravitational force is always calculated as "mg," regardless of whether the object is in motion.
  • Another participant discusses the nature of gravitational fields and the equivalence principle, stating that the difference between being stationary in a gravitational field and accelerating is an illusion, reinforcing the idea of balancing forces.

Areas of Agreement / Disagreement

Participants generally agree on the calculation method for gravitational force, but there are differing interpretations regarding the conceptual understanding of gravitational acceleration and its implications in the context of the problem.

Contextual Notes

There are unresolved nuances regarding the interpretation of gravitational acceleration and its application in non-free-fall scenarios, as well as the implications of the equivalence principle in understanding forces.

gnickg
I am no science or physics major but this is my first quiz. I have this problem:
How much force must be applied to accelerate a 10,000-kg space shuttle to counter the Earth's gravitational acceleration of 9.8 meters per second square?
I took 9.8m/s^2 * 10,000 for 98,000 Newtons.
Is that correct?
Your help is much appreciated!
gnickg
 
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Yep.

Followup: the space shuttle accelerates at roughly 3g's at liftoff. What's the force? (careful, its a bit of a trick question)
 
Originally posted by gnickg
I am no science or physics major but this is my first quiz. I have this problem:
How much force must be applied to accelerate a 10,000-kg space shuttle to counter the Earth's gravitational acceleration of 9.8 meters per second square?
I took 9.8m/s^2 * 10,000 for 98,000 Newtons.
Is that correct?
Your help is much appreciated!
gnickg

So far so good. Here's a conceptual helping hand: "g" is always called "acceleration due to gravity," but that's a misnomer (wrong name). An object only has an acceleration equal to "g" when it is in free fall in a vaccuum.

Think of "g" as the gravitational field intensity, and no matter what is happening, the gravitational force on something will be "mg" . A lot of people get confused by multiplying mass times an "acceleration" when the darn thing isn't going anywhere!

Hope this is helpful.
 
It's an acceleration vector field, equivalent to accelerating at 9.8 m/s2 away from a massless earth. By the equivalence principle, the difference between being stationary in a vector field and accelerating is an illusion.
gnickg this problem is about finding where forces balance, balanced forces are equal to each other- you solved it the right way.
 
Thanks everyone for your help on my physics question. I got an "A"...!
 

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