Solving Limits - Questions on x^(sinx) & (9^x)/(8^x)

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The discussion addresses two limit problems: lim x-> 0+ x^(sinx) and lim x-> +inf (9^x)/(8^x). The first limit evaluates to 1, confirmed by the expression e^0 = 1. The second limit simplifies to (9/8)^x, where 9/8 is greater than 1, leading to the conclusion that the limit approaches infinity as x approaches positive infinity. The behavior of exponential functions based on their base values is also highlighted.

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Hello, I have two questions concerning limits

1) lim x-> 0+ x^(sinx)
2) lim x-> +inf. (9^x)/(8^x)

The first one gives me 1 (e^0 = 1) .. is that correct?
The 2nd one I don't know how to do. Can someone please explain the 2nd one for me?
Thanks a lot
 
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1) Correct

2) (9^x)/(8^x) = (9/8)^x and 9/8 > 1. How does a^x behave if a<1, a=1, a>1 ?
 
Gokul43201 said:
1) Correct

2) (9^x)/(8^x) = (9/8)^x and 9/8 > 1. How does a^x behave if a<1, a=1, a>1 ?


I knew it was that simple! Thanks for the help :)
 

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