Solving Improper Integrals: $\int_2^{inf} \frac{2}{(x+3)^{3/2}}$

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Homework Help Overview

The discussion revolves around evaluating the improper integral $\int_2^{\infty} \frac{2}{(x+3)^{3/2}}$, focusing on the limit process and convergence of the integral.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to evaluate the integral and expresses confusion regarding the limit as \( b \) approaches infinity. Participants question the behavior of the function as \( x \) approaches infinity and discuss the implications of their findings.

Discussion Status

Participants are exploring the limit of the function as \( x \) approaches infinity, with some suggesting that it converges to zero. There is an acknowledgment of potential errors in calculations, and a collaborative atmosphere is present as participants clarify each other's points.

Contextual Notes

The original poster mentions a mistake in their calculations and expresses uncertainty about the proper method to find the limit. There is an indication of a need for clearer understanding of the limit process in the context of improper integrals.

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[tex]\int_2^{inf} \frac{2}{(x+3)^{3/2}}[/tex]

integrating the problem, i get:
[tex]\frac{-4}{sqrt(x+3)}[/tex]

now integrating from 2 to inf(replaced with b), plugging in 2, i get -4/5:
f(b) + 4/5
lim->inf

it looks like f(b), lim->inf goes to -4 X 10^-inf

so wouldn't the answer just be divergent? i also tried 4/5 and -4/5, but it wouldn't work. i don't really know the proper way to find the limit. all i do is plug in the largests number and try to find a pattern.
 
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What is [tex]lim_{x \rightarrow \infty}\frac{1}{x^n}[/tex] where n is any positive real number ?
 
looks like it goes to zero
 
yes, but i still don't get it... what are you trying to tell me?


are you saying that f(b),lim->inf goes to zero? and the answer should be 4/5?
 
ah, thanks for the help. actually, f(2) is not equal to 4/5, i typed it wrong in my calculator. i need some sleep, thanks agian.
 
I realize that i didn't bother to do the calcuation for you and that's why i agreed with you...:wink:

Daniel.
 

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