How far the peg is driven into the ground due to impact?

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SUMMARY

The discussion focuses on calculating how far a wooden peg is driven into the ground upon impact with a mallet. The peg has a mass of 0.4 kg, while the mallet weighs 2 kg, resulting in a combined mass of 2.4 kg. The peg's initial velocity is 6.67 m/s, and the ground exerts an opposing force of 1 kN. By applying Newton's second law (F=ma) and the work-energy principle, the deceleration is calculated to be 2.77917 m/s², allowing for the determination of the distance the peg travels before coming to a stop.

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Basic principles of kinetic energy
  • Familiarity with work-energy theorem
  • Ability to perform calculations involving mass, force, and acceleration
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  • Calculate the distance using the formula: distance = (initial velocity²) / (2 * deceleration)
  • Explore the relationship between kinetic energy and work done by external forces
  • Investigate the effects of different masses and forces on impact distance
  • Learn about energy conservation in impact scenarios
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Physics students, engineers, and anyone interested in mechanics and impact analysis will benefit from this discussion.

Gughanath
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a wooden peg is hit vertically by a mallet which is also moving vertically. The mass of the peck is 0.4kg and the mallet is 2kg. The speed at which the peg starts to move into the ground is 6.67m/s. Given that the ground opposes the motion of the peck with a force of 1kN, find how far the peg is driven into the ground due to impact? Please help me on this one??
 
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Think of it as a mass of 2.4 Kg traveling at 6.67m/s, decelerating at a rate which you can derive from F=ma as it drives into the ground. Calculate the distance for the object to stop.

If you calculate the acelleration the force of the ground gives, you can ask a simpler question by working backwards a bit ; At a=2.77917 ms-2 what distance is traveled to reach 6.67 m/s

:edit to clarify post:
 
Last edited:
Wouldn't it be simple to use kinetic energy. The peck has some kinetic energy and the ground does negative work to the peck with a force of 1kN. Just find when the kinetic energy equals the work done by the ground.
 

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