# Thevenin Equivalent Circuit: using open/short circuit method

by november1992
Tags: circuit, equivalent, method, open or short, thevenin
 P: 120 1. The problem statement, all variables and given/known data http://i.imgur.com/fSRqw.png 2. Relevant equations $V_{th}$ = $V_{oc}$ 3. The attempt at a solution I got the thevenin voltage by using node voltage $\frac{V2-40}{5}$ - $\frac{80+2V2}{5}$ -8 + V2 = 0 ($\frac{1}{5}$ + $\frac{2}{5}$ + 1)V2 = 32 $\frac{8}{5}$V2 = 32 V2 = 20V = Vth but I don't know how to setup the equation to find the short-circuit current. Since there's a short circuit, I believe that means no current goes through the 1 ohm resistor. I tried using a source transformation, but I got 28A as the current. Since Rth is 0.625, then the current has to be 32A. http://i.imgur.com/6Twjp.png