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how do you take the natural logs?? |
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| Feb19-05, 08:13 PM | #1 |
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how do you take the natural logs??
I think this is why I can't do my problems, maybe i'm missing some basic concepts.
ok, so let [tex] L({\theta}) = \theta^{-2n} \prod y e^{-(1/theta)}\sum y [/tex] taking the natural log, I get [tex]ln L(\theta) = -2nln\theta + ln \prod y - 1/\theta \sum yi [/tex]. I dont know, how did they do that? and later, I will need to differentate it too, but and I dont know how to do it either. but for that one, how did they do it? |
| Feb19-05, 10:23 PM | #2 |
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I can't make sense of what you've written. Indices and parentheses would help. Anyway, whatever that first expression is supposed to be, there's a good chance you will be able to simplify the logarithm considerably by using log(xy)=log x + log y repeatedly.
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