# Calculate the Second Ionization Energy of Lithium

by pasido
Tags: energy, ionization, lithium
 P: 3 1. The problem statement, all variables and given/known data Given -Total Energy for $Li \rightarrow Li ^{3+} = 1.960 * 10^{4} kJ/mol$ -First Ionization Energy of Li = $5.20 * 10^{2} kJ/mol$ 2. Relevant equations Other than the equation in the image, I used the equation: Etotal = E1 + E2 + E3 3. The attempt at a solution Since Etotal and E1 are given, I have E2 and E3 left to solve. To solve for E3, I used the equation in the picture. Li^2+= A hydrogen atom (1 electron), I used the equation in the picture to solve for the energy for a single electron. Energy = -1.962*10^-17 J The problem is, I don't know what to do with that number. How do I convert energy of a single electron to ionization energy?
 P: 415 That energy is the energy you need to supply to the electron in order to overcome coulombic forces, i.e. to ionize the species. Simple enough.