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Calculate the Second Ionization Energy of Lithium

by pasido
Tags: energy, ionization, lithium
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pasido
#1
Oct18-12, 09:49 AM
P: 3
1. The problem statement, all variables and given/known data


Given
-Total Energy for [itex]Li \rightarrow Li ^{3+} = 1.960 * 10^{4} kJ/mol[/itex]

-First Ionization Energy of Li = [itex]5.20 * 10^{2} kJ/mol[/itex]

2. Relevant equations
Other than the equation in the image, I used the equation:
Etotal = E1 + E2 + E3

3. The attempt at a solution
Since Etotal and E1 are given, I have E2 and E3 left to solve.

To solve for E3, I used the equation in the picture.

Li^2+= A hydrogen atom (1 electron), I used the equation in the picture to solve for the energy for a single electron. Energy = -1.962*10^-17 J

The problem is, I don't know what to do with that number. How do I convert energy of a single electron to ionization energy?
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AGNuke
#2
Oct18-12, 12:29 PM
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P: 456
That energy is the energy you need to supply to the electron in order to overcome coulombic forces, i.e. to ionize the species. Simple enough.
Borek
#3
Oct18-12, 12:35 PM
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P: 23,597
Quote Quote by pasido View Post
How do I convert energy of a single electron to ionization energy?
What is a mole?


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