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Calculate the Second Ionization Energy of Lithium 
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#1
Oct1812, 09:49 AM

P: 3

1. The problem statement, all variables and given/known data
Given Total Energy for [itex]Li \rightarrow Li ^{3+} = 1.960 * 10^{4} kJ/mol[/itex] First Ionization Energy of Li = [itex]5.20 * 10^{2} kJ/mol[/itex] 2. Relevant equations Other than the equation in the image, I used the equation: Etotal = E1 + E2 + E3 3. The attempt at a solution Since Etotal and E1 are given, I have E2 and E3 left to solve. To solve for E3, I used the equation in the picture. Li^2+= A hydrogen atom (1 electron), I used the equation in the picture to solve for the energy for a single electron. Energy = 1.962*10^17 J The problem is, I don't know what to do with that number. How do I convert energy of a single electron to ionization energy? 


#2
Oct1812, 12:29 PM

PF Gold
P: 456

That energy is the energy you need to supply to the electron in order to overcome coulombic forces, i.e. to ionize the species. Simple enough.



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