Calculating Initial Separation of Charged Particles Using Conservation Laws

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Homework Help Overview

The discussion revolves around calculating the initial separation between two charged particles using conservation laws. The problem involves two particles with known masses and charges that are released from rest, leading to their separation and subsequent speeds at a given distance apart.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using conservation of momentum to find the velocities of the particles after release. There is a transition to considering conservation of energy, specifically kinetic and electric potential energy, to find the initial separation. Questions arise regarding the implications of zero change in electric potential energy and the correct expressions for energy between charged particles.

Discussion Status

Some participants have provided guidance on using conservation of energy principles, while others are exploring the relationship between electric potential energy and kinetic energy. There is an ongoing examination of the relevant equations and concepts, with no explicit consensus reached on the final approach.

Contextual Notes

Participants are navigating the complexities of energy conservation in the context of charged particles, questioning assumptions about potential energy and its calculations. The discussion reflects a mix of understanding and confusion regarding the application of energy conservation in this scenario.

NotaPhysicsMan
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Ok here's the question:

One particle has a mas of 3.00 x10^-3 kg and a charge of +8.00uC. A second particle has a mass of 6.00x10^-3 kg and the same charge. The two particles are initally held in place and then released. The particles fly apart, and when the separation between them is 0.100m, the speed of the 3.00x10^-3kg particle is 125m/s. Find the inital separation between the particles.

Ok, I think I can start by using conservation of momentum to solve for V2.

So m1V1 + m2V2= m1V1(final)+m2V2(Final)

Since my inital velocities are 0, I'm left with the two final terms.

I want V2, so V2=(-m1/m2)V1.

Ok so V2=-62.5m/s.

Now I'm stuck.
Should I be using the conservation of energy next?

Thanks for the input!
 
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Yes, you should use conservation of energy next.

--J
 
Ok so I don't have rotational, gravitational, or spring but I do have kinetic and Electric Potential energy.

So: Inital(1/2m1v1^2+EPE1)+(1/2m2v2^2+EPE2)=Final(1/2m1v1^2+EPE1)+(1/2m2v2^2+EPE2)

Since I have 0m/s from rest, my inital terms are no more for kinetic energy.

The only thing I can find for this is

Delta EPE initial - Delta EPE final= 1/2mv1^2+1/2mv2^2.

So delta EPEi-EPEf=1/2(3.00 x10^-3 kg)(125m/s)^2 +1/2( 6.00x10^-3 kg )(-62.5m/s)^2.

Ok so I have the Delta EPEi-EPEf value as 0, which is unsual I can't use it anywhere.

Maybe I should have found the Voltage instead?
 
NotaPhysicsMan said:
Ok so I have the Delta EPEi-EPEf value as 0, which is unsual I can't use it anywhere.

Why would this be zero? Do you know an expression for the energy between two charged particles?

--J
 
F=k|q1||q2|/r^2 is this the one you're talking about?
 
Ok I'm lost now.

I've used cons of momentum to find V2. Where am I to go now?

KEf +EPEf=KEi+EPEi?

Ok I can use this to solve for? Since KEi can be eliminated, we have EPEi=KEf+EPEf.

So qVi=1/2mv^2 + qVf. Ok now extremely lost!
 
Ok do you know how to calculate electric potential energy??

Wht is the initial potential energy?
and the final?
Intial = final + something

figure out what the something is. The something is an aenergy and its not gravitational because that's negligible in this case.
 
Kinetic Energy?
 
NotaPhysicsMan said:
Kinetic Energy?
yes and it is the kinetic energy of both the particles

intial = final + kinetic energies of both and solve for the initial distance

do you know that the electric potential energy is just like gravitational potential energy? i.e. [tex]P_{E} = - \frac{kq_{1}q_{2}}{r}[/tex]
 
  • #10
That's odd, I thought EPE=qV is the electrical potential energy.
 
  • #11
NotaPhysicsMan said:
That's odd, I thought EPE=qV is the electrical potential energy.
what is the expression for V??
 
  • #12
aahh yes, qV and V=kq/r.

I see and yes my answer to the question came out to be 0.01407 m just by following what you had said before:

PEi=PEf+(KE1+KE2) I just solved for the r in the PEi.

Thanks.
 

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