# What is the wavelength of the light？

by atsum
Tags: light&#, wavelength
 Homework Sci Advisor HW Helper Thanks P: 12,447 How do you know the answer is wrong? It can help if you do the algebra first, then use more convenient units:$$\lambda=\frac{8(m_e c^2) L^2}{hc}\frac{1}{n_f^2-n_i^2}$$ ##hc=1.240\text{eV$\mu$m}## ##m_ec^2=511\text{eV}## ##L=0.0052\text{$\mu$m}## ... give it a go. (Don't forget to check my algebra to get that equation.)
 Quote by Simon Bridge How do you know the answer is wrong? It can help if you do the algebra first, then use more convenient units:$$\lambda=\frac{8(m_e c^2) L^2}{hc}\frac{1}{n_f^2-n_i^2}$$ ##hc=1.240\text{eV$\mu$m}## ##m_ec^2=511\text{eV}## ##L=0.0052\text{$\mu$m}## ... give it a go. (Don't forget to check my algebra to get that equation.)