What Does a ≡ b (mod m) Imply in Mathematics?

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Homework Help Overview

The discussion revolves around the mathematical concept of congruences, specifically the notation a ≡ b (mod m). Participants are seeking clarification on its meaning and implications, particularly in the context of integer values and modular arithmetic.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to understand the definition of congruences and how to apply them, with some questioning the validity of certain examples and interpretations, especially regarding the use of fractions in modular equations.

Discussion Status

There is an ongoing exploration of the meaning of the congruence relation, with some participants providing definitions and examples. However, there is no explicit consensus on the interpretation of specific cases, particularly involving fractions and their manipulation within modular arithmetic.

Contextual Notes

Some participants express confusion regarding the application of congruences when non-integer values are involved, and there is mention of constraints related to the values of m and b in specific examples.

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What exactly does this mean?
a=b (mod m)
My teacher didn't attempt explain this but I'd still like to know.
 
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[itex]a \equiv b \mod m[/itex], means [itex]a[/itex] is a multiple of [itex]m[/itex] plus [itex]b[/itex]. (a,b and m are integers)

It means when you divide a by b, you get a rest of m.

In algebra, a,b and m are not necessarily integers, but in most cases they are.
 
Last edited:
So how do you solve (2/3)= x (mod 5) for x?
I'm told that x=4, but if m<|b|, then that can't be right.
 
What exactly does this mean?
a=b (mod m)
For integers "a", "b", and "m" (m > 0),
a = b (mod m)
if and only if (a - b) is exactly divisible by "m" (or equivalently, that "a" divided by "m" has the same remainder as "b" divided by "m").

Example:
10 = 4 (mod 3)
---> (10 - 4)/3 = Integer
---> {10 divided by 3} has same remainder as {4 divided by 3}


~~
 
Last edited:
yay_goobers2112 said:
So how do you solve (2/3)= x (mod 5) for x?
I'm told that x=4, but if m<|b|, then that can't be right.
I'm sorry, that remark was wrong. Just use the second one: :biggrin:

[itex]a \equiv b \mod m[/itex] means division of a by b will give rest m.

I'ven't seen fractions on the left side of congruences before, but they probably mean (multiplying both sides by 3):

[tex]2 = 3x \mod 5[/tex]

or

[tex]2-3x = 0 \mod 5[/tex]
So 2-3x must be a multiple of 5, so x =4 will work.
 

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