Percent Abundance of Br-81 in Bromine

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The percent abundance of Br-81 in bromine is calculated to be 45%. This conclusion is derived using the formula: % abundance of Br-81 = (atomic mass of Br - atomic mass of Br-79) / (atomic mass of Br-81 - atomic mass of Br-79) * 100. Given that the atomic mass of bromine is 79.9, the calculation shows that 45 out of every 100 bromine atoms are Br-81, with the remaining 55 being Br-79. This method effectively utilizes the known atomic masses of the isotopes to determine their relative abundances.

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  • Understanding of atomic mass and isotopes
  • Familiarity with basic algebraic manipulation
  • Knowledge of the isotopes of bromine, specifically Br-79 and Br-81
  • Ability to apply percentage calculations
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  • Study the concept of isotopic abundance in chemistry
  • Learn about atomic mass calculations for multiple isotopes
  • Explore the implications of isotopic ratios in chemical reactions
  • Investigate the applications of isotopes in fields such as radiometric dating
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Chemistry students, educators, and professionals involved in analytical chemistry or isotope research will benefit from this discussion, particularly those focusing on isotopic abundance and atomic mass calculations.

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Br consists of Br-79 and Br-81. The atomic mass of Br is 79.9. Find the % of Br-81 in bromine.
 
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Do you know a formula for calculating the atomic mass from percentages of different isotopes?

Atomic mass is equal, in this case, to:

[(Br-79 percentage abundance/100) x 79] + [(Br-81 percentage abundance/100) x 81]


Because you know the atomic mass and not the abundances, let percentage abundance of Br-81 be X. Then you can write an expression for the percentage abundance of Br-79, and so can calculate the value you need.
 


The percent abundance of Br-81 in bromine can be calculated using the following formula:

% abundance of Br-81 = (atomic mass of Br - atomic mass of Br-79) / (atomic mass of Br-81 - atomic mass of Br-79) * 100

Plugging in the values given in the question, we get:

% abundance of Br-81 = (79.9 - 79) / (81 - 79) * 100
% abundance of Br-81 = 0.9 / 2 * 100
% abundance of Br-81 = 0.45 * 100
% abundance of Br-81 = 45%

Therefore, the percent abundance of Br-81 in bromine is 45%. This means that out of every 100 atoms of bromine, 45 of them will be Br-81 and the remaining 55 will be Br-79.
 

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