Last Minute Help

Dooh

I have been spending nearly 3 hours on this lab write up that is due tomorrow. since i had missed a couple days of school, there are somethings that i was not introduced to therefore this is kinda hard for me. I managed to figure out most part but this is what i'm stuck on right now.

Part of the experiment requires us to mix 2g of NaOH with water and calculate the amount of heat evolved. This question asked: suppose to had used 8g of NaOH instead, what would have been the number of calories evolved in the experiment and what effect would this have on change if Heat? I keep thinking its four times more but thats going to only apply to the temperature. So is there anyone on this late at night taht can help me?

chem_tr

Sodium hydroxide gives x calories per mole upon dissolution; so 2 grams of NaOH (m.w.=40 grams/mol) will give Q₁=x/20 calories, since this is 1/20 moles. If you use 8 grams of NaOH, you'll get Q₂=x/5 calories. This is because 8 grams of NaOH is 0.2 moles.