How Does Increasing NaOH Mass Affect Heat Evolution in a Lab Experiment?

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SUMMARY

The discussion focuses on the relationship between the mass of sodium hydroxide (NaOH) and the heat evolved during its dissolution in water. Specifically, when 2 grams of NaOH is mixed with water, it yields Q1 = x/20 calories, while using 8 grams results in Q2 = x/5 calories, indicating that the heat evolved increases proportionally with the amount of NaOH. The molar mass of NaOH is 40 grams/mol, which is crucial for calculating the moles involved in the reaction. Thus, increasing the mass of NaOH from 2g to 8g results in an increase in heat evolution by a factor of four.

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I have been spending nearly 3 hours on this lab write up that is due tomorrow. since i had missed a couple days of school, there are somethings that i was not introduced to therefore this is kinda hard for me. I managed to figure out most part but this is what I'm stuck on right now.

Part of the experiment requires us to mix 2g of NaOH with water and calculate the amount of heat evolved. This question asked: suppose to had used 8g of NaOH instead, what would have been the number of calories evolved in the experiment and what effect would this have on change if Heat? I keep thinking its four times more but that's going to only apply to the temperature. So is there anyone on this late at night taht can help me?
 
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Sodium hydroxide gives x calories per mole upon dissolution; so 2 grams of NaOH (m.w.=40 grams/mol) will give Q1=x/20 calories, since this is 1/20 moles. If you use 8 grams of NaOH, you'll get Q2=x/5 calories. This is because 8 grams of NaOH is 0.2 moles.
 

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