A Question on Integrating Expansions of Infinities

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The discussion centers on the integral of the function e^{-x^2} from 0 to infinity, which equals \(\frac{\sqrt{\pi}}{2}\). It highlights the confusion surrounding the Taylor series expansion of e^{-x^2} and the resulting infinite sum, specifically \(\sum_0^{\infty}\frac{a_n{\infty}^{n+1}}{n!(n+1)}\). The participants emphasize the importance of limits and the conditions under which limits and summation can be interchanged, noting that this is a fundamental concept in analysis. The recommended method for evaluating the integral involves squaring it and using polar coordinates to simplify the calculation.

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eljose
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A question on infinities...

we all know that the function [tex]e^{-x^2}[/tex] can be expanded into a taylor series my question arises when we try to perform the integral:

[tex]\int_0^{\infty}exp(-x^2)=\frac{sqrt\pi}{2}[/tex]

then if we expand exp(-x^2) in terms of its Taylor series and perform the integration we would find that:

[tex]\frac{sqrt\pi}{2}=<br /> \sum_0^{\infty}\frac{a_n{\infty}^{n+1}}{n¡(n+1)}[/tex]

the question is if a sum of infinities can give a finite number such as happens in the last sum... where the a_n are the taylor coefficients of the series expansion for exp(-x^2)
 
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The sum makes no sense: you're not even adding up real numbers. At least take limits first, and then ask if it is permissible to interchange limits and summation signs. (answer, not always - this is basic analysis, not number theory.)
 
To evaluate the integral, the simplest approach that works is first square it, then change the variables in the double integral to polar coordinates. You will then very easily get pi/4 for the squared integral.
 

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