Nov26-12, 08:49 AM
A couple M will be applied to a beam of rectangular cross section from a log of circular cross section. determine the ratio d/b so that maximum stress will be minimum
σmax = M(d/2)/((1/12)bd3)
σmax = 6M/(b*d2)
and d2 + b2 = D2
D =diameter of the circle
but i can't find the ratio..
i know the answer of d/b is sqrt 2
how can i get the answer?
do i need differentiate?
if yes how should i do the differentiation??
|Register to reply|
|Bending of Beams||Introductory Physics Homework||5|
|beams and bending||Engineering, Comp Sci, & Technology Homework||7|
|Bending Beams||Engineering, Comp Sci, & Technology Homework||1|
|bending of beams||Engineering, Comp Sci, & Technology Homework||1|
|Bending of J Beams||Mechanical Engineering||6|