The Effect of Electric Field on Proton Motion

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Homework Help Overview

The discussion revolves around the motion of a proton in an electric field, specifically focusing on the relationship between electric potential energy and electric potential as the proton moves within the field. Participants are examining the implications of the proton's movement in relation to the direction of the electric field and the associated changes in energy and potential.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants are exploring the correct interpretation of potential energy and electric potential as the proton moves in the electric field. Questions are raised regarding the definitions of terms like "k" and the significance of the charge in the equations presented. There is also an inquiry into the relationship between potential energy and potential, with analogies drawn to gravitational fields.

Discussion Status

The discussion is active, with participants questioning initial assumptions and clarifying concepts. Some guidance has been offered regarding the behavior of positive charges in electric fields, and there is an exploration of the implications of this behavior on potential energy and potential. Multiple interpretations are being considered, particularly regarding the correct answer to the original question posed by the original poster.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the depth of exploration into the problem. There is an ongoing discussion about the assumptions related to the movement of the proton and the nature of the electric field created by two charges of opposite sign.

Soaring Crane
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For a proton moving in the direction of the electric field

a. its potential energy increases and its electric potential decreases
b. its potential energy increases and its electric potential increases
c. its potential energy decreases and it electric potential increases
d. its potential energy dcreases and its electric potential decreases


Originally, I thought the answer was b, but this is wrong. Exactly why is b incorrect and what exactly is the correct choice?

Thanks.
 
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electric potential energy [tex]U = k \frac{q_{1} q_{2}}{r}[/tex]
electric potential [tex]V = k \frac{q_{not proton}}{r}[/tex]

since the proton moves in line with the field, it is moving + to - or vice versa??
Now that you knwo the direction you can see what happens in the initial and final conditions
calculate the electric potential energy and electric potential of the proton when it close to the positive end and the negative end, assuming that there are TWO charges of opposite sign creating this field. You know the direction which is bigger than which??
if the values went down then it obviously decreased and if the values went up then increase
 
Hey stunner. A couple questions:
What's "k"?
And what does the charge in the electric potential equation stand for if its not that of the p+?
 
Soaring Crane said:
Originally, I thought the answer was b, but this is wrong. Exactly why is b incorrect and what exactly is the correct choice?
Here's a hint: Positive charges accelerate toward regions of lower potential. (Assuming there are no other forces acting on them.) How do potential and potential energy relate?

Compare this to a ball falling in a gravitational field. Which way does the field point? Where is the PE greater?
 
DB said:
What's "k"?

[tex]k = \frac{1} {4 \pi \epsilon_{0}}[/tex]
 
Ahh, so electrical potential energy is the same as coulombs law?
 
No, Coulomb's law is for the force between two charges.
 
Well, since that hint is true, is it d where both decrease?
 
Soaring Crane said:
Well, since that hint is true, is it d where both decrease?
That's right. The field points toward the region of lower potential. The proton accelerates as it moves through the field, losing potential energy and gaining kinetic energy. (Assuming no other forces act.)
 

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