How Does Electric Field Influence Current Flow in a PN Junction Diode?

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SUMMARY

The discussion focuses on the influence of electric fields on current flow in a PN junction diode, specifically addressing the recombination of charge carriers and the role of electric fields in establishing equilibrium. When P-type and N-type semiconductors contact, holes from the P-side and electrons from the N-side recombine, creating a small current. Under equilibrium conditions, there is no net current in an unbiased PN junction, as the diffusion current from free carriers balances the electric field-induced current. The electric field exerts a force on charge carriers, resulting in current flow, similar to metals but differing in charge carrier types.

PREREQUISITES
  • Understanding of semiconductor physics, specifically P-type and N-type doping.
  • Knowledge of charge carrier dynamics, including recombination and diffusion processes.
  • Familiarity with electric field effects on charge carriers in both metals and semiconductors.
  • Basic concepts of equilibrium in semiconductor junctions.
NEXT STEPS
  • Study the principles of charge carrier recombination in semiconductors.
  • Learn about the effects of electric fields on charge carriers in semiconductor devices.
  • Explore the concept of transient diffusion currents in PN junctions.
  • Investigate the differences between current flow in metals and semiconductors.
USEFUL FOR

Electrical engineers, semiconductor physicists, and students studying electronic devices will benefit from this discussion, particularly those interested in the operational principles of PN junction diodes.

020170
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when it comes to pn junction in diode, p and n are doping semiconductors.

if P and N semiconductor are contacting each other,

some holes in P and some electron in N are combined. that is, they are recombined.

this recombination caused the current, very small.

I was wondering that where did this current flow. did it flow through N? or P?



Another Question : in depletion layer, when the current due to the free carrier

diffusion equals the current caused by the electric field, and the pn junction

reaches equilibrium. I knew that electric field make the current
when metal like Cu is moving back and forth between electric field.

but in pn junction, how did electric field make the current?
 
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020170 said:
when it comes to pn junction in diode, p and n are doping semiconductors.

if P and N semiconductor are contacting each other,

some holes in P and some electron in N are combined. that is, they are recombined.

this recombination caused the current, very small.

I was wondering that where did this current flow. did it flow through N? or P?
Under equilibrium, there is no current in an unbiased PN junction. The recombination is simply the "annihilation" of free electrons by free holes near the interface, due to diffusion from a difference in chemical potential. You may choose to refer to this recombination process in terms of a transient diffusion current, in which case, a positive transient current would have flowed from the p-type to the n-type SC.



Another Question : in depletion layer, when the current due to the free carrier

diffusion equals the current caused by the electric field, and the pn junction

reaches equilibrium. I knew that electric field make the current
when metal like Cu is moving back and forth between electric field.

but in pn junction, how did electric field make the current?
The process is the same, whether it's a metal or semiconductor. The electric field exerts a force on the free charge carriers in the conduction band. The result of this force (along with phonon/impurity scattering) is a current along the direction of the field.

The only real differences are in the nature of the majority charge carriers (in pure Cu, these are electrons; in p-type Si, these are holes) and the mechanism by which the conduction band is populated.
 

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