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Energy transfer in electromagnetic induction |
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| Dec31-12, 10:39 AM | #35 |
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Energy transfer in electromagnetic induction
Well, when the magnet is given a 'nudge', this will cause a change in the surrounding EM field which will propagate at c. (Which is due to the theory of retarded potentials in the Lorenz gauge). (And by 'propagate at c', I simply mean that after time t, the furthest point at which the EM field is affected by the nudge is at distance ct).
This is true whether or not the coil is there. And if the coil is there, it will take time x/c after the nudge, for the EM field at the coil to be affected. So it is at this time that the current can be induced in the coil, Then the propagation of this effect will again travel at c, so it will take another time of x/c for the magnet to experience the field which is due to currents which have been induced in the coil. |
| Dec31-12, 11:10 AM | #36 |
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I know I haven't immediately answered your questions, but I have not thought about this problem before, so I am trying to start with the principles that I am most certain should apply to this situation.
So, for the questions. Are they real waves? Um, I guess they satisfy the inhomogeneous wave equations. So yes? But then by this definition, every classical electromagnetic phenomena involves real waves. If we instead define a real wave as being oscillatory, then I guess generally the waves in this case would be partly real and partly not. I would expect the accelerating magnet to emit EM energy even if the coil was not there. For example, if the magnet was made of a coil with current flowing through it, then when we nudge the magnet, we are accelerating charges, which generally gives off EM radiation. |
| Dec31-12, 01:41 PM | #37 |
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| Dec31-12, 02:56 PM | #38 |
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The delay for the magnet to experience resistance due to the current in the coil seems to be 2x/c. Indeed, If we follow the classical approach the delay seems to be 2x/c. But if we look at it from QED perspective it seems to be 0. (Wheeler Feynman absorber theory) Can we throw more light on it looking at it from the relativity perspective? After all magnetic field can be explained as an effect due to the "length contraction" involving moving charges using theory of relativity. I have seen papers which explain the origin of magnetic fields using relativity. Most of them have to do with the forces of attraction/repulsion between two wires carrying current. But I have not come across any which explain electromagnetic induction with the same approach. I know it would be too complicated, but in case any of you have come across it, please help. |
| Jan4-13, 10:12 AM | #39 |
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Drakkith has got a good point. There are two different situations 1) considering a magnet which is being given a 'nudge' by some person. 2) considering a magnet which is moving toward the coil, with no 'outsider' forces.
I have mostly been talking about what happens when the magnet is given a 'nudge' i.e. acceleration. In this case, there is a delay before the effect is felt by the coil. I am pretty sure that Wheeler Feynman absorber theory also predicts that there is a time delay. But because I don't know much QFT, I can't say with complete certainty. Now in the case when the magnet is moving freely (not being 'nudged'), then I am not so sure about whether there is a delay in the reaction force being felt, because in this case, at any particular time, there is already a magnetic field travelling between the magnet and the coil (which is due to the magnet moving at an earlier time). |
| Jan4-13, 02:30 PM | #40 |
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However, the magnet will feel small resistance immediately. This is due to the fact that one part of the surface current will act on another, an in case the magnet is accelerated, these forces do not cancel each other but tend to act against the acceleration. This is sort of a "self-inductance" effect. Later, after time 2x/c, the wave from the coil will come and damp the magnet as well. This will be typically much greater effect (sort of "mutual inductance"). |
| Jan5-13, 01:47 PM | #41 |
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Suppose that the magnet is initially at rest. It is given a push at time t=t1. Lets assume that the kinetic energy transferred to the magnet due to this push is Ek. This kinetic energy may decrease immediately due to radiation or self inductance but the effect is negligible. Now at time t=t1+(x/c) we have the current induced in the coil and it has gained energy due to this induced current. Now since the magnet does not experience any resistance till t1+(2x/c) i.e any considerable resistance we can see that the magnet does not lose the kinetic energy acquired by it during the initial push till t1+(2x/c). So between t1+(x/c) and t1+(2x/c) we have this energy in the coil as well as in the kinetic energy of the magnet. The kinetic energy of the magnet is the cause for the current to be induced in the coil. The magnet just transfers its kinetic energy to the coil through mutual induction. So should not the kinetic energy of the magnet decrease before the current is induced in the coil? |
| Jan5-13, 02:23 PM | #42 |
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You are probably worried about conservation of energy, but I think there is no problem. The currents in the coil get their energy from the field near the wires. Eventually, the magnet will lose some kinetic energy, but this is merely an after-effect. |
| Jan5-13, 03:00 PM | #43 |
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The energy stored inside the magnetic field is constant. If the current gets energy from the field surrounding the coil, how can it obtain more and more energy from this field as the velocity of the magnet increases. If the magnet is moving with a sufficiently high velocity the current induced in the coil may increase beyond what the surrounding magnetic field can provide. |
| Jan5-13, 03:09 PM | #44 |
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So this should get rid of the energy conservation problems. In this case the resistance is felt immediately rather than 2x/c. |
| Jan5-13, 03:33 PM | #45 |
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The energy of the field is the higher the higher is the velocity of the magnet. We can be sure that there is always enough energy present to maintain the energy conservation, because we have the Poynting theorem; this shows that the energy is conserved locally, and moves through space like fluid.. I agree it is difficult to imagine this in such complicated process, but there is an alternative way of description, via EM forces, which makes this much more clear. According to the Faraday law, the magnitude of the electric field due to magnet animating the currents is the higher the higher is the velocity of the magnet; the higher the electric field, the stronger currents get induced. |
| Jan5-13, 03:55 PM | #46 |
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Mentor
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I see the scenario as follows: 1) magnet and coil at rest wrt each other, no forces 2) force on magent to accelerate magnet (extra force required in order to generate E field) 3) EM wave propagates at c to coil 4) changing current induced in coil 5) changing field produced by coil 6) EM wave propagates at c to magnet 7) coil field opposes motion of magnet I recommend against throwing unnecessary quantum concepts into any discussion which can be done purely classically. Generally it adds more confusion than understanding. |
| Jan5-13, 06:30 PM | #47 |
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Edit: So I guess I'm saying that if we only considered mutual inductance, then energy is not conserved when we give the magnet a nudge. (But this is because we are not considering the whole picture). |
| Jan5-13, 06:36 PM | #48 |
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| Jan6-13, 02:46 AM | #49 |
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Thanks for replying to my queries. One more thing here, suppose that we replace the magnet with an electromagnet. The current in the electromagnet is controlled by a switch. Also we will remove the coil.(which was originally placed at a distance x) Initially the electromagnet is not powered on and hence no magnetic field would be present. Now we nudge this electromagnet so that it starts moving at a constant velocity. Next the electromagnet is switched on so that it produces a magnetic field. Now since it is moving, it should try putting energy to the electromagnetic field. So wont this oppose the current flowing in the electromagnet itself? trying to decrease the magnetic field. |
| Jan6-13, 02:48 AM | #50 |
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| Jan6-13, 10:17 AM | #51 |
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