Energy Required to Lift a Heavy Box

  • Thread starter Thread starter ProBasket
  • Start date Start date
  • Tags Tags
    Box Energy Lift
Click For Summary

Homework Help Overview

The discussion revolves around the physics of lifting a heavy box using a pulley system. The original poster describes a scenario where they attempt to lift a box of mass m with an ideal pulley and a massless rope, seeking to determine the force required to lift the box at constant velocity.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between the force applied to the rope and the weight of the box, questioning the mechanical advantage provided by the pulley. There are differing opinions on whether the force required is mg or mg/2, with some participants suggesting the need for a diagram to clarify the setup.

Discussion Status

The discussion is ongoing, with participants providing differing viewpoints on the mechanics of the pulley system. Some guidance has been offered regarding the force required, but there is no consensus yet on the correct interpretation of the pulley configuration.

Contextual Notes

There is a noted confusion regarding the attachment of the pulley, with participants emphasizing the importance of accurately understanding the setup to determine the force needed. A diagram has been suggested to aid in this clarification.

ProBasket
Messages
140
Reaction score
0
As you are trying to move a heavy box of mass [tex]m[/tex], you realize that it is too heavy for you to lift by yourself. There is no one around to help, so you attach an ideal pulley to the box and a massless rope to the ceiling, which you wrap around the pulley. You pull up on the rope to lift the box.


A.) What is the magnitude [tex]F[/tex] of the upward force you must apply to the rope to start raising the box with constant velocity?
Express the magnitude of the force in terms of [tex]m[/tex], the mass of the box.


I think the answer should be mg/2

is this correct?
 
Physics news on Phys.org
Yes. The pulley gives you a mechanical advantage, reducing the force (but not the energy!) needed to lift the box.
 
The pulley won't make it any easier. The force you'll need to apply with a single pulley is still F=mg.

...

Edit: Hmm... I think I might have mistaken the way the pulley is connected, in which case the force may be mg/2. A diagram would be nice!
 
With a single pulley the way you described it there's no way to shorten the distance over which the force is applied (it is the same as the distance over which the pulley rises). So the force is still mg. The only facilitation is that you apply the force downward.
 
Please reread the original post: The pulley is attached to the box, not the ceiling.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
18K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 38 ·
2
Replies
38
Views
6K
  • · Replies 7 ·
Replies
7
Views
15K
  • · Replies 26 ·
Replies
26
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 4 ·
Replies
4
Views
3K