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The translational force on a piece of iron in a magnetic field |
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| Feb9-13, 12:09 PM | #1 |
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The translational force on a piece of iron in a magnetic field
Ok so if there be a piece of iron in a uniform magnetc field B, what will be the force on the iron?
You can assume any variable you want, but i want to find the magnetic force that causes the iron pieces to move towards the magnet in terms of any variables, like it corss-sectional area, length, position etc. |
| Feb9-13, 02:46 PM | #2 |
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The net force is 0. There might be a torque, depending on the orientation of the iron and its magnetic field (if present) and the external magnetic field.
You need a field which is not uniform to move magnets. |
| Feb9-13, 10:04 PM | #3 |
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| Feb10-13, 07:13 AM | #4 |
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The translational force on a piece of iron in a magnetic field
The iron bar will get a magnetic field similar to the external field, and this multiplied with the gradient of the external field should give some reasonable estimate for the force.
http://en.wikipedia.org/wiki/Force_between_magnets |
| Feb11-13, 02:58 AM | #5 |
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But then what to do? I need to find the developed pole strengths first, right? How do I do that? |
| Feb11-13, 12:15 PM | #6 |
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A magnet does not consist of two separate poles. If you know the magnetic field (and assume it is the same everywhere in the magnet), it is fine.
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| Feb11-13, 09:19 PM | #7 |
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Have I got a misconception about these things? Please help me. I am absolutely at a loss now! |
| Feb12-13, 09:36 AM | #8 |
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I think it is a detour. It is possible, but you just multiply with things (like the volume) and divide by them again afterwards.
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| Feb12-13, 09:51 AM | #9 |
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Ok... One more thing, does the developed pole strength at each end of the iron bar change with its position? I think the pole strength will keep varying as a function of the field the iron bar is in. Am I right?
By using the properties of the material, I got an equation for the pole strength. Its given by, s=χBA/μ , where χ is the susceptibility of iron, B is the field it is kept in, A is its cross-sectional area and μ is the permeability of the surrounding medium. Is this correct? |
| Feb12-13, 02:54 PM | #10 |
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| Feb12-13, 09:50 PM | #11 |
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I→=M→/V=M→/A.l=s.l.M^/Al=M^s/A Then again, χ=I→/H→=I→μ/B→... and then the above expression of the pole strength |
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