Calculating Forces and Work on a Sliding Piano

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SUMMARY

The discussion focuses on calculating forces and work associated with a 393 kg piano sliding down a 27° incline, where a man exerts a force to prevent acceleration. The effective coefficient of kinetic friction is 0.40. Key calculations include the force exerted by the man, work done by the man, friction force, gravity, and net work using the work-energy theorem. The equation utilized is ΔW = ΔE_k + ΔE_g + ΔE_s + ΔE_f + F_man, where ΔE_k and ΔE_p represent kinetic and potential energy changes, respectively.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the work-energy theorem
  • Knowledge of kinetic and potential energy equations
  • Basic grasp of friction and its coefficients
NEXT STEPS
  • Calculate the force exerted by the man using F = m * g * sin(θ) - friction force
  • Determine the work done by the man using W = F * d * cos(θ)
  • Analyze the work done by friction using W_friction = -friction force * distance
  • Explore the implications of the work-energy theorem in different scenarios
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in understanding the dynamics of forces and work in inclined planes.

VoxFox
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A 393 kg piano slides 3.7 m down a(n) 27° incline and is kept from accelerating by a man who is pushing back on it parallel to the incline. The effective coefficient of kinetic friction is 0.40.
(a) Calculate the force exerted by the man.
(b) Calculate the work done by the man on the piano.
(c) Calculate the work done by the friction force.
(d) Calculate the work done by the force of gravity.
(e) Calculate the net work done on the piano.
 
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What have you done so far on the question? Can you post it please? What are your ideas on how to attack it? We can guide you from there. But not do a whole problem from scratch for you.
 
the whole problem can be solved by using one equation, the work energy theorem:
[tex]\Delta W = \Delta E_k + \Delta E_g + \Delta E_s + \Delta E_f + F_man[/tex]

you should know what each segment eans in the equation.
for ex. [tex]\Delta E_k = \frac{1}{2}m{v_{2}}^2 - \frac{1}{2}m{v_{1}}^2[/tex]
[tex]\Delta E_p = mgh_2 - mgh_1[/tex]

If you need more help, please indicate which part of the problem you don't understand.

Regards,

Nenad
 

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