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Magnitude of Force on Wrench 
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#1
Feb2113, 08:20 PM

#2
Feb2113, 08:31 PM

P: 31

What if θ was zero? According to your formula, this would give a torque of Fd (because cos(0) = 1). But, if you look at the picture, if θ = 0, shouldn't the torque be 0 as well? You are just pulling straight out; this shouldn't turn the bolt at all.
Hint: is θ really the angle between the force and the displacement? 


#3
Feb2113, 09:09 PM

P: 12




#4
Feb2113, 09:13 PM

P: 31

Magnitude of Force on Wrench



#5
Feb2213, 12:57 PM

P: 12

I figured out that the answer is 1.89810^{2}N
F=45F*m/(0.300m*sin(52.6°)) 


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