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Indefinite Integral of (3x^210)/(x^24x+4) dx using PARTIAL FRACTION 
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#1
Feb2713, 04:29 PM

P: 3

1. The problem statement, all variables and given/known data
Integrate (3x^210)/(x^24x+4) dx using partial fractions. 2. Relevant equations None 3. The attempt at a solution I tried using A/(x2) + B/(x2)^2 but I didnt get a coeffecient of an x^2. I've also tried using (Ax+B)/(x2) + C/(x2)^2 Though I honestly thought that the usual A/(x2) + B/(x2)^2 would work, How do I know which formula to use. I know you have to do long division if the numerator has an x to a larger value than that of the denominator. I know when you have something like: (x^21) or (x^3+2) in the denominator then you use the Ax+B, Cx+D formula. 


#2
Feb2713, 04:33 PM

HW Helper
P: 1,347

[tex]\frac{A}{x  2} + \frac{B}{(x  2)^2}[/tex] ... because the denominator is a linear factor squared. But before you try partial fractions, you have to use long division because the degrees of the numerator and denominator are the same. 


#3
Feb2713, 04:34 PM

P: 778

The degree of the numerator is equal to the degree of the denominator. Try long division before partial fraction decomposition.



#4
Feb2713, 05:02 PM

Sci Advisor
HW Helper
Thanks
P: 5,081

Indefinite Integral of (3x^210)/(x^24x+4) dx using PARTIAL FRACTION
[tex] 3x^210 = 3(x^24x+4)+12x  22.[/tex] 


#5
Feb2713, 07:52 PM

P: 3

Ah, so if the degree of the numerator and that of the denominator are the same then you have to use long division, didnt know that. Thanks a lot guys it worked out well.



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