Rolling rigid object

priya

<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no,location=no, scrollbars=yes,resizable=yes,status=no,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>Hi,\n\nI\'m trying to study the motion of a rigid object on a rail. I have a\nvery basic question in dynamics. Suppose, a ball is rolling on a\nstraight rail (\nwith two point of contacts) what are the reaction forces ?. The\nvertical component can be assumed to be equal and found by equating to\nthe weight. The horizontal components are also equal and opposite. But\nis there any way to find the value for the horizontal component?\n\nI will highly appreciate an answer to this question.\n\nHank you,\nPriya\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">  View this Usenet post in original ASCII form </a></div><P></jabberwocky>Hi,

I'm trying to study the motion of a rigid object on a rail. I have a
very basic question in dynamics. Suppose, a ball is rolling on a
straight rail (
with two point of contacts) what are the reaction forces ?. The
vertical component can be assumed to be equal and found by equating to
the weight. The horizontal components are also equal and opposite. But
is there any way to find the value for the horizontal component?

I will highly appreciate an answer to this question.

Hank you,
Priya

Igor Khavkine

<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','toolbar=no,location=no, scrollbars=yes,resizable=yes,status=no,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usenet ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>priya wrote:\n> Hi,\n>\n> I\'m trying to study the motion of a rigid object on a rail. I have a\n> very basic question in dynamics. Suppose, a ball is rolling on a\n> straight rail (\n> with two point of contacts) what are the reaction forces ?. The\n> vertical component can be assumed to be equal and found by equating\nto\n> the weight. The horizontal components are also equal and opposite.\nBut\n> is there any way to find the value for the horizontal component?\n>\n> I will highly appreciate an answer to this question.\n\nThe force exerted by the rails is normal to the plane of contact.\nThe plane of contact in this geometry is tangent to the ball at the\npoint of contact. This gives you the direction of the reaction force\n(toward the center of the ball from the point of contact). Since you\nknow one of the components (the vertical one) using some trigonometry\nyou can figure out the other components.\n\nHope this helps.\n\nIgor\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form">  View this Usenet post in original ASCII form </a></div><P></jabberwocky>priya wrote:
> Hi,
>
> I'm trying to study the motion of a rigid object on a rail. I have a
> very basic question in dynamics. Suppose, a ball is rolling on a
> straight rail (
> with two point of contacts) what are the reaction forces ?. The
> vertical component can be assumed to be equal and found by equating
to
> the weight. The horizontal components are also equal and opposite.
But
> is there any way to find the value for the horizontal component?
>
> I will highly appreciate an answer to this question.

The force exerted by the rails is normal to the plane of contact.
The plane of contact in this geometry is tangent to the ball at the
point of contact. This gives you the direction of the reaction force
(toward the center of the ball from the point of contact). Since you
know one of the components (the vertical one) using some trigonometry
you can figure out the other components.

Hope this helps.

Igor

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