Two Lense Problem: Solving A, B & C

  • Thread starter Thread starter Jacob87411
  • Start date Start date
Click For Summary
SUMMARY

The discussion focuses on solving a two-lens problem involving a converging lens with a focal length of 20 cm and another with a focal length of 5 cm, separated by 50 cm. For part A, the image position of an object placed 40 cm in front of the first lens is determined using the lens formula 1/f = 1/do + 1/di, applied twice. Part B addresses the height of the final image, which can be calculated once the image position is known. Part C involves finding the image position of an object placed 5 cm in front of the two lenses in contact, following a similar approach as in part A.

PREREQUISITES
  • Understanding of lens formulas, specifically 1/f = 1/do + 1/di
  • Knowledge of image formation by converging lenses
  • Basic skills in drawing scale diagrams for optical systems
  • Familiarity with magnification calculations for lenses
NEXT STEPS
  • Learn advanced lens systems and their applications in optics
  • Study the concept of effective focal length for multiple lens systems
  • Explore ray tracing techniques for complex optical setups
  • Investigate the impact of lens aberrations on image quality
USEFUL FOR

Students studying optics, physics educators, and anyone interested in understanding the principles of image formation using multiple lenses.

Jacob87411
Messages
170
Reaction score
1
A converging lens of focal length 20 cm is separated by 50 cm from a converging lens of focal length 5 cm. (A) Find the final positiom of the image of an object placed 40 cm in front of the first lens. (B) If the height of the object is 2 cm, what is the height of the final image. (C) Determine the image position of an object placed at 5 cm in front of the two lens in contact.

I am having some issues with two lense problems.

A)In A if the image is 40 cm infront of the first lens it is 10 from the second. The image will come up somewhere inbetween the two? I am assuming I need the equation 1/f=1/d0 + 1/di, but do I use it twice or what.

B) This one isn't that bad, once I find A this shouldn't be an issue.

C) Part C is sort of just like A, once I can figure out how to solve A this one shouldn't be that bad.
 
Physics news on Phys.org
Jacob87411 said:
A)In A if the image is 40 cm infront of the first lens it is 10 from the second. The image will come up somewhere inbetween the two? I am assuming I need the equation 1/f=1/d0 + 1/di, but do I use it twice or what.

Yes, you have to use it twice. First, pretend the second lens isn't there, and find the position of the image that the first lens produces. Second, pretend that the first lens isn't there any more, put the second lens back where it was, and pretend that the object is located at the image position that you calculated in the first step. In other words, the image produced by the first lens becomes the object for the second lens. It's a good idea to make a scale drawing to keep track of where everything is, and see how the distances fit together.
 
Alright thanks, that makes sense
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K