Poisson stats: signal to noise

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Homework Help Overview

The discussion revolves around a problem in astrophysics related to measuring the apparent magnitude of a star and calculating the uncertainty in that measurement using signal-to-noise ratios. The subject area includes concepts from statistics and error propagation in the context of astronomical observations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between apparent magnitude, signal, and noise, questioning how to derive the flux-area product (fA) from the given information. There are attempts to apply logarithmic relationships and error propagation techniques, with some participants expressing uncertainty about specific calculations and assumptions.

Discussion Status

The discussion is active, with participants sharing different approaches to the problem. Some guidance has been offered regarding the use of error propagation and the relationship between signal and noise, though there is no explicit consensus on the correct method or outcome yet.

Contextual Notes

Participants note potential complications related to RMS noise and the definitions of variables involved in the calculations. There is also mention of an arbitrary constant K, which is under discussion regarding its implications for the problem.

StephenPrivitera
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A star was measured to have an apparent magnitude m=16 with S/N=10 integrated over a minute. What is the uncertainty in the measurement?
signal=flux*area*time
noise=sqrt(signal)=sqrt(fAt)
So, S/N=sqrt(fAt)
How can I find fA?
m=-2.5logfAt+K
16=-2.5log(fAt)+K
Hoping that K is arbitrary (please verify this), I choose K=0
Then 16=-2.5log(fAt)
So fA=3.98 e-7 J/s (units inconsequential)
So, uncertainty =6.3 e-4
??
HELP!
edit:
Or, I can get N=uncertainty=sqrt(S/10)=sqrtS <--- something VERY wrong here
 
Last edited:
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I think this is an exercise in error propagation.
m=-2.5logfAt+K

You could also write m=-2.5log(I)+K
You have m, and I/dI=10. You want to find dm. (d means differential).

m + dm = -2.5log(I + dI) + K.
You could now substitute dI = I/10, and solve for m. That will work, since I will cancel.

However, I suspect they talk about RMS noise.
Which makes things a bit more complicated.
 


Originally posted by arcnets

However, I suspect they talk about RMS noise.
Which makes things a bit more complicated.
No, actually. You're answer if perfect. We went over this today in class. It didn't make sense then, but I think it's finally making sense. I was trying to hard to find S.
 

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