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Is this 'e' interpretation correct? 
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#1
Apr713, 05:19 AM

P: 190

Considering e is the limit>+oo of (1+1/n)^n, then is e "what you get if you wait for the least gain, by waiting for the most amount of time"? Something like "e is the patience number".



#2
Apr713, 05:32 AM

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Hmm..No.



#3
Apr713, 05:57 AM

P: 190




#4
Apr713, 06:09 AM

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Is this 'e' interpretation correct?



#5
Apr713, 07:11 AM

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which, for every particular choice of "n" will have a less gain waited for for an even greater period of time than the one you happende to pick. 


#6
Apr813, 08:46 AM

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What explanation could be given when you haven't said what you mean by "gain" or "waiting".



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