<jabberwocky><div class="vbmenu_control"><a href="jabberwocky:;" onClick="newWindow=window.open('','usenetCode','to olbar=no,location=no,scrollbars=yes,resizable=yes, status=no,width=650,height=400'); newWindow.document.write('<HTML><HEAD><TITLE>Usene t ASCII</TITLE></HEAD><BODY topmargin=0 leftmargin=0 BGCOLOR=#F1F1F1><table border=0 width=625><td bgcolor=midnightblue><font color=#F1F1F1>This Usenet message\'s original ASCII form: </font></td></tr><tr><td width=449><br><br><font face=courier><UL><PRE>I browsed through David Gross\' Nobel lecture slides (URL below) and\nnoticed the following quote of Landau (1960):\n\n"We reach the conclusion that within the limits of formal\nelectrodynamics a point interaction is equivalent, for any intensity\nwhatever, to no interaction at all. We are driven to the conclusion\nthat the Hamiltonian method for strong interaction is dead and must be\nburied, although of course with deserved honor."\n\nWhat does Landau mean? The N-point function seems to be based on the\nintegral of the Hamiltonian density, time-ordered and exponentiated,\nno?\n\nhttp://nobelprize.org/physics/laureates/2004/gross-slides.pdf\n\n</UL></PRE></font></td></tr></table></BODY><HTML>');"> <IMG SRC=/images/buttons/ip.gif BORDER=0 ALIGN=CENTER ALT="View this Usenet post in original ASCII form"> View this Usenet post in original ASCII form </a></div><P></jabberwocky>I browsed through David Gross' Nobel lecture slides (URL below) and
noticed the following quote of Landau (1960):
"We reach the conclusion that within the limits of formal
electrodynamics a point interaction is equivalent, for any intensity
whatever, to no interaction at all. We are driven to the conclusion
that the Hamiltonian method for strong interaction is dead and must be
buried, although of course with deserved honor."
What does Landau mean? The N-point function seems to be based on the
integral of the Hamiltonian density, time-ordered and exponentiated,
no?
http://nobelprize.org/physics/laurea...oss-slides.pdf