- #1
Owen-
- 40
- 0
This seems like a very basic question that I should know the answer to, but in my image processing class, my teacher explained that a basis set of images(matrices) are orthonormal.
He said that the DOT product between two basis images (in this case two 2x2 matrices) is 0. so, for example
\begin{equation}
\begin{bmatrix}
a & b\\
c & d
\end{bmatrix}
\cdot
\begin{bmatrix}
e & f\\
g & h
\end{bmatrix}
=0
\end{equation}
I don't understand how this can be. I always thought it gave another matrix, and not a direct value:
\begin{equation}
\begin{bmatrix}
a & b\\
c & d
\end{bmatrix}
\cdot
\begin{bmatrix}
e & f\\
g & h
\end{bmatrix}
=
\begin{bmatrix}
ae+bg & af+bh\\
ce+dg & cf+dh
\end{bmatrix}
\end{equation}
Can someone help me out? It would be unbelieveably helpful,
Thanks!
Owen.
He said that the DOT product between two basis images (in this case two 2x2 matrices) is 0. so, for example
\begin{equation}
\begin{bmatrix}
a & b\\
c & d
\end{bmatrix}
\cdot
\begin{bmatrix}
e & f\\
g & h
\end{bmatrix}
=0
\end{equation}
I don't understand how this can be. I always thought it gave another matrix, and not a direct value:
\begin{equation}
\begin{bmatrix}
a & b\\
c & d
\end{bmatrix}
\cdot
\begin{bmatrix}
e & f\\
g & h
\end{bmatrix}
=
\begin{bmatrix}
ae+bg & af+bh\\
ce+dg & cf+dh
\end{bmatrix}
\end{equation}
Can someone help me out? It would be unbelieveably helpful,
Thanks!
Owen.