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Centripetal Accelerationby oneplusone
Tags: centripetal 
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#1
Jul913, 06:29 PM

P: 127

Hello, my textbook says that the magnitude
of centripetal acceleration is equal to the sum of the forces acting on that object. (this is in regard to an object in a circular path, by a string. See https://upload.wikimedia.org/wikipedia/commons/thumb/c/c9/Centripetal_force_diagram.svg/220pxCentripetal_force_diagram.svg.png for an example) I was wondering why is this so? To me, it doesn't make sense that they are equal in magnitude, since the forces are perpendicular. Please help. 


#2
Jul913, 06:49 PM

HW Helper
P: 7,110




#3
Jul913, 07:18 PM

P: 127

So could you please briefly describe how will you solve for Tension? generically?



#4
Jul913, 09:24 PM

HW Helper
P: 7,110

Centripetal Acceleration



#5
Jul1013, 07:43 AM

P: 127



#6
Jul1013, 07:59 AM

HW Helper
P: 7,110

Looking at that diagram, there are no other forces acting on the mass other than centripetal force, which equals m v^2 / r or m ω^2 r. The centripetal acceleration would be v^2 / r or ω^2 r.



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