Parabolic Headlight where should bulb be located Locus and Conic unit

  • Thread starter Thread starter aisha
  • Start date Start date
  • Tags Tags
    Bulb Unit
Click For Summary

Homework Help Overview

The discussion revolves around the placement of a bulb in a parabolic headlight reflector, specifically determining its location at the focus of the parabola. Participants are exploring the properties of parabolas in the context of locus and conics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to identify the correct equation for the parabola and its focus. Questions arise regarding the interpretation of the diagram and the coordinates involved. There is also a discussion about the significance of the point (8,16) and its relation to the parabola's properties.

Discussion Status

The discussion is active, with participants sharing equations and questioning the validity of points derived from the parabola. Some guidance has been offered regarding the properties of parabolas and their foci, but no consensus has been reached on the exact placement of the bulb.

Contextual Notes

Participants are working with a diagram that may not be to scale, and there are uncertainties regarding the coordinate system and the specific characteristics of the parabola in question. The problem is framed as an application of locus and conics, but some participants express doubt about the assumptions being made.

aisha
Messages
584
Reaction score
0
http://ca.pg.photos.yahoo.com/ph/sikandar1984/detail?.dir=9181&.dnm=8e2e.jpg&.src=ph

This link is a diagram for this question

It says the cross section of a parabolic reflector of a headlight is shown in the diagram. Determine where the bulb should be located if it is positioned at the focus?

Um what is the cross section? The x and y axis? Where they meet?

Do I have to find an equation? Or coordinate? Or do I just describe where it should be?

This is an application question for locus and conics I think this is an application with a parabola conic but not too sure. I have an equation for the bulb but its probably wrong, it is

[tex]x^2= \frac {1} {32} y^2[/tex]

this is the equation of a parabola conic opening towards the right like the diagram. Please help me out! Thanks
 
Last edited by a moderator:
Physics news on Phys.org
aisha said:
[tex]x^2= \frac {1} {32} y^2[/tex]

this is the equation of a parabola conic opening towards the right like the diagram. Please help me out! Thanks
The equation for this parabola is:

[tex]y^2 = 4px[/tex] where p is the focus

So if the point (8,16) is on the parabola, what is p?

That is where you would put the light bulb. At that point all lines to the parabola reflect parallel to the x-axis - which makes it a beam of light.

[Note: the parabola is obviously not drawn to the proper scale.]

AM
 
Last edited:
where did u get the point (8,16) is this parabola opening towards the right like the diagram?
 
aisha said:
where did u get the point (8,16) is this parabola opening towards the right like the diagram?

Your picture shows that at 8 units from the vertex, the "width" of the parabola is 32: If your coordinate system is set up so that (0,0) is at the vertex then 1/2 of that 32 is positive, 1/2 negative. Choosing positive x to the right, positive y upward, that corresponds to x= 8, y= 32/2= 16 or y= -32/2= -16.

aisha said:
This is an application question for locus and conics I think this is an application with a parabola conic but not too sure.

aisha, Don't you believe what YOU write? The problem SAYS "a parabolic reflector". Why would you be "not too sure" it really IS a parabola?
 
the light bulb will be at point 8,0

8 being the focus when i subbed a point into the equation :smile:
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 5 ·
Replies
5
Views
11K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
15
Views
42K